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musickatia [10]
3 years ago
5

Write the number 393,234,000,034 in words.

Mathematics
2 answers:
Butoxors [25]3 years ago
5 0

Answer:

Three hundred and ninety three billion, two hundred and thirty four million and thirty four.

Step-by-step explanation:

GarryVolchara [31]3 years ago
3 0

Answer:

three hundred and ninety three billion, two hundred and thirty four million, and thirty four.

Step-by-step explanation:

billion is any digit that has seven to nine digits behind it

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8 divided by 2/3 in a word problem
sattari [20]

Answer:

12

Step-by-step explanation:

8/1 ÷ 2/3

Keep the first fraction and flip the second one: 8×3/ 1×2

Multiply top and bottom: 24÷2

Simplified to be 12

7 0
2 years ago
Find the slope of the line passing through the points (-4.0) and (7,0)
Veronika [31]

slope = (y2-y1)/ (x2-x1)

m = (0-0)/ (7--4)

m = 0/11

m=0

the slope is 0

4 0
3 years ago
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Easy multiplication and division question
Zigmanuir [339]

The minimum amount of sheets she can use are 4 sheets. 3 sheets contain 10 cookies, and 1 sheet has 6 cookies.

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3 years ago
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According to a recent​ survey, the population distribution of number of years of education for​ self-employed individuals in a c
creativ13 [48]

Answer:

a) X: number of years of education

b) Sample mean = 13.5, Sample standard deviation = 0.4

c) Sample mean = 13.5, Sample standard deviation = 0.2

d) Decrease the sample standard deviation

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

X: number of years of education

Central limit theorem:

If large random samples are drawn from population with mean \mu and standard deviation \sigma, then the distribution of sample mean will be normally distributed with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

b) mean and the standard for a random sample of size 49

\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{49}} = 0.4

c) mean and the standard for a random sample of size 196

\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{196}} = 0.2

d) Effect of increasing n

As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

7 0
3 years ago
Kira unravels a shirt to get blue thread. From each centimeter (cm) of the shirt, Kira gets 231 cm of thread. She unravels 7cm o
cricket20 [7]

Answer:

1617 cm of thread.

Step-by-step explanation:

We are told that the equivalence would be that for each cm of shirt Kira gets 231 cm of thread, therefore it would be:

231 cm thread / 1 cm shirt

they tell us that she managed to remove 7 cm of shirt, therefore:

7 cm shirt * 231 cm thread / 1 cm shirt = 1617 cm thread

Therefore Kira obtained 1617 cm of thread.

6 0
2 years ago
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