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baherus [9]
3 years ago
7

In a bookcase, there are

Mathematics
1 answer:
Oksanka [162]3 years ago
7 0

Answer:

20 Books

Step-by-step explanation:

You might be interested in
Han's house is 450 meters from school. Lin’s house is 135 meters closer to school. How far is Lin’s house from school?
Marina86 [1]

Solution:

<u>Note that:</u>

  • Han's house = 450 m from school
  • Lin's house = (450 - 135) from school

<u>Looking at the options, we can tell that the letter "z" represents Lin. </u>

  • => z = (450 - 135)
  • => z = 450 - 135

This option matches with Option D.

Option D is correct.

6 0
3 years ago
2. In the triangle below, NE and KL are perpendicular bisectors. Knowing that the sum of interior angles in
Stells [14]

Answer:

a = 60°

Step-by-step explanation:

From the picture attached,

In the given triangle,

NE and ML are the perpendicular bisectors of two sides of the triangle.

Therefore, m∠MEK = m∠MLK = 90°

Since, sum of interior angles of polygon KLME = 360°

m∠MEK + m∠MLK + m∠EML + m∠EKL = 360°

90° + 90° + 120° + a = 360°

a = 360° - 300°

a = 60°

5 0
3 years ago
Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
3 years ago
Declan has n baseball cards. Sam has 4 times as many baseball cards as Declan. Amaya has 7 fewer baseball cards than Sam. Which
marishachu [46]
Answer: 4n -7

Sam has 4 times than Declan so it would 4n. Amaya has fewer so then you would add the -7 and the equation you get is 4n - 7.
4 0
3 years ago
You are comparing prices from 2 office supply stores. Your office needs 5 cases of blue paper. Home &amp; Office Headquarters li
melomori [17]


5x[$25.85-($25.85 x 0.10) ] + (5 x 2.50)=$128.83 compared to[ 5 x 27.36( $27.36 x 0.15)]+ 10.00= 126.28 is the least amount.

answer is ------> $126.28

8 0
3 years ago
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