In the diagram below, A C ≅ C E , and D is the midpoint of CE. If CE = 10x+18, DE = 7x-1, and BC = 9x+2, find AB.
2 answers:
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Answer:
Step-by-step explanation:
observe
||a–b+c|| = ||a+b+c||
(a-b+c)² = (a+b+c)²
(a+b+c)² – (a-b+c)² = 0
((a+b+c)+(a-b+c))((a+b+c)–(a-b+c)) = 0
(2a+2c)(2b) = 0
(a+c)b = 0
a•b + c•b = 0
||a||×||b||×cos(π/8) + ||c||×||b||×cos(θ) = 0
The periodicity of function is
<em><u>Solution:</u></em>
Given that we have to find the period of function
<em><u>Given function is:</u></em>
<em><u>Use the below formula:</u></em>
Thus,
Now find the periodicity of cos(x)
We know that,
periodicity of cos(x) =
Therefore,
Thus the periodicity of function is