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astra-53 [7]
3 years ago
8

True False for each

Mathematics
1 answer:
Alex777 [14]3 years ago
5 0

Answer:

can you please add a picture

Step-by-step explanation:

I can't work it out without no picture

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What is the volume of both shapes ?
Nataly [62]

Answer:

314 ft cubed

Step-by-step explanation:

To find the volume, find the volume of the cone and add it to the volume of the cylinder.

The volume of a cone is

V= \frac{1}{3}\pi r^2 h=  \frac{1}{3}\pi (5^2)(12) =  \frac{1}{3}\pi (25)(12)= \frac{1}{3}\pi *300 = 100\pi.

The volume of the cylinder is

V=\pi (5^2)(4)= \pi (25)(4)= 100\pi

Together their volume is 100\pi+100\pi=200\pi \\200\pi =314ft^3

6 0
3 years ago
Solve the following inequality. <br><br>−1
erica [24]

Answer:

any thing, not 1 or -1

Step-by-step explanation:

the equality to any number is either itself or its opposite 1 inequality would be 2-infinite or -2- -infinite and zero

7 0
3 years ago
Read 2 more answers
Justify each step of the proof.
WARRIOR [948]
 <span>I assume that the x is squared 
(on Yahoo!Answers, we often use the caret ^ to show a power or an exponent) 
(think of it as a tiny arrow pointing up, showing that the following number should be seen as if it were raised above the line) 

2(x^2 + 5) = 60 

Can it be x = 5 ? 
we test: 
2(5^2 + 5) = 2(25 + 5) = 2(30) = 60 
it works, therefore x = 5 is a solution. 

Can it be x = -5? 
we test again: 
2[(-5)^2 + 5) = 2(25 + 5) = 2(30) = 60 
it works, therefore x = -5 is also a solution. 

The way you did it, there could be some confusion between step 4 and step 5 (because you do not explain how you go from 4 to 5). 
If you simply "take the square root" on both sides, someone could argue that the "principal" square root of a number is the positive value (+5 only, not -5). On the other hand, if you state: 
(after step 4), we look for all values that give 25 when they are squared, then -5 is allowed. 

The way the conjecture is stated at the beginning, the easiest way is to check both values to find out that, yes, they are both valid solutions.</span>
7 0
3 years ago
Three coins are dropped on a table.
Dominik [7]

Answer:

(a) S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

(b) \frac{1}{8}

(c) \binom{3}{2} (\frac{1}{2})^3 = \frac{3}{8}

(d) (\frac{1}{2})^3 + \binom{3}{1} (\frac{1}{2})^3 = \frac{1}{8} + \frac{3}{8} = \frac{1}{2}

(e) 1 - \frac{1}{2} = \frac{1}{2}

(f) Yes, because P(A \cap B) = 0. Therefore P(A \cup B) = P(A) + P(B) = \frac{3}{8} + \frac{1}{2} = \frac{7}{8}

(g) No, because P(A \cap C) = \frac{3}{8}. Therefore P(A \cup C) = P(A) + P(C) - P(A \cap C) = \frac{3}{8} + \frac{1}{2} - \frac{3}{8} = \frac{1}{2}

8 0
3 years ago
Mrs. redding needs 24 juice boxes for her class. The juice boxes come in packages of 9. How many packages does she need?
vladimir2022 [97]

9 x 3, you can't exactly get 24 juice boxes. Therefore, Mrs. Redding needs 3 packages.

7 0
4 years ago
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