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3 years ago

I forgot how to do some maths so i need help: solve 2x + 3 = -1

Mathematics

2 answers:

Pavel [41]3 years ago

6 0

2x + 3 = -1
-3 = -3

2x = -4
— —
2 2

x = -2

Hope this makes sense and helps :)

Leviafan [203]3 years ago

3 0

Hi student, let me help you out! :)

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We are asked to solve the equation $\pmb{2x+3=-1}$ .

$\triangle~\fbox{\bf{KEY:}}$

The goal is to isolate x.

First, subtract 3 from both sides of the equal sign:

$\mathrm{2x=-1-3}$

$\mathrm{2x=-4}$

Now, divide both sides by 2:

$\mathrm{x=-2}$

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

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Answer:

The negation to the given statement "At least one gift in the bag is wrapped - true" is " At least one gift in the bag is not wrapped" - False

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Step-by-step explanation:

Given statement is At least one gift in the bag is wrapped is true

The negation to the given statement is " At least one gift in the bag is not wrapped" - False

<u>To determine whether the statement is a negation of the given statement is True or False :</u>

<h3> At least one gift in the bag is not wrapped - False </h3><h3> Not every gift in the bag is wrapped-True </h3><h3>Every gift in the bag is wrapped-False </h3><h3>None of the gifts in the bag are wrapped-False</h3>

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3 years ago

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

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Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

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20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

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