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The value of integration of y=16- from x=-1 to x=1 is 94/3.
Given the equation y=16- and the limit of the integral be x=-1,x=1.
We are required to find the value of integration of y=16- from x=-1 to x=1.
Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.
Integration is basically opposite of differentiation.
y=16-
Find the integration of 16-.
=16x-
Now find the value of integration from x=-1 to x=1.
=16(1)--16(-1)-
=16(1)-1/3+16-1/3
=32-2/3
=(96-2)/3
=94/3
Hence the value of integration of y=16- from x=-1 to x=1 is 94/3.
Learn more about integration at brainly.com/question/27419605
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One way would be to find the distance from the point to the center of the circle and compare it to the radius
for
the center is (h,k) and the radius is r
and the distance formula is
distance between
and 
is
r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so
the radius is
center is (-2,3)
find distance between (8,4) and (-2,3)
≈4.2
≈10.04
do r<D
(8,4) is outside the circle
for
the center is (h,k) and the radius is r
and the distance formula is
distance between
r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so
the radius is
center is (-2,3)
find distance between (8,4) and (-2,3)
do r<D
(8,4) is outside the circle