Ask question

Ask question

All categories

3 years ago

12

PLEASE HELP, What is the "weight" or value of one circle in this hanger? In other words, what does one "W" have to be for this t

o be true?

1 answer:

Ierofanga [76]3 years ago

5 0

Answer:

Step-by-step explanation:

W = 25/4 = 6.25

You might be interested in

Through: (-5, -3), perp. to y=-9/4x-5

Mrrafil [7]

Given:

A line passes through (-5,-3) and perpendicular to $y=-\dfrac{9}{4}x-5$ .

To find:

The equation of the line.

Solution:

We have,

$y=-\dfrac{9}{4}x-5$

On comparing this equation with slope intercept form, i.e., $y=mx+b$ , we get

$m_2=-\dfrac{9}{4}$

It means, slope of this line is $-\dfrac{9}{4}$ .

Product of slopes of two perpendicular lines is always -1.

$m_1\times m_2=-1$

$m_1 \times \left(-\dfrac{9}{4}\right)=-1$

$m_1=\dfrac{4}{9}$

Slope of required line is $\dfrac{4}{9}$ and it passes through the point (-5,-3). So, the equation of the line is

$y-y_1=m(x-x_1)$

where, m is slope.

$y-(-3)=\dfrac{4}{9}(x-(-5))$

$y+3=\dfrac{4}{9}(x+5)$

$9(y+3)=4(x+5)$

$9y+27=4x+20$

$27-20=4x-9y$

$7=4x-9y$

Therefore, the equation of required line is $4x-9y=7$ .

8 0

3 years ago

Two equivalent decimals for 2.50

Ad libitum [116K]

2.5 is an equivalent decimal because you can add infinity zeros after the last number in a decimal and it will still be the same.

&

2.500 would be an equivalent decimal because you can add infinity zeros after the last number in a decimal and it will still be the same.

2.5, 2.500, 2.5000, 2.50000, etc..

5 0

3 years ago

Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .

Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of $F$ around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

$F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle$

Therefore,

$P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y$

Let's calculate the needed partial derivatives.

$P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0$

Thus,

$Q_x -P_y = 0 -2 = - 2$

Now, by the Green's theorem, we have

$\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x \Big|_{-3}^{4} = -42$

4 0

3 years ago

Which of the following sets of data will have the smallest Standard Deviation?

uranmaximum [27]

Answer: D

Step-by-step explanation:

Standard Deviation σ2 =

Σ(xi - μ)2/N

=(1 - 5.3)2 + ... + (9 - 5.3)2/10

=68.1/10

= 6.81

σ = √6.81

= 2.60959767014

B) σ2 =

Σ(xi - μ)2/N

=(3 - 61.7)2 + ... + (99 - 61.7)2/10

=58414.1/10

= 5841.41

σ = √5841.41

= 76.429117488036

C) (1 - 11.4)2 + ... + (1 - 11.4)2/10

=8758.4/10

= 875.84

σ = √875.84

= 29.59459410095

D) (79 - 79)2 + ... + (79 - 79)2/10

=0/10

= 0

σ = √0

= 0

I hope this helps, mark as Brainliest please.

6 0

3 years ago

Cherie is jogging around a circular track. She

skelet666 [1.2K]

Answer:

Measure of minor angle JOG is $95.5^{\circ}$

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.

$\therefore m JG = 200 yards, JO=120 yards$ .

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle $\angle JOG = \theta$ .

To calculate the central angle, use the arc length formula as follows.

$Arc\:Length\left(s\right) = r\:\theta$

Where $\theta$ is measured in radian.

Substituting the value,

$200=120\:\theta$

Dividing both side by 120,

$\dfrac{200}{120}=\theta$

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

$\therefore \dfrac{5}{3}=\theta$

Therefore value of central angle is $\angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}$ , since angle is in radian

Now convert radian into degree by using following formula,

$1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}$

So multiplying $\theta$ with $\left(\dfrac{180}{\pi}\right)^{\circ}$ to convert it into degree.

$\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}$

Simplifying,

$\therefore \theta = 95.49^{circ}$

So to nearest tenth, $\angle JOG=95.5^{circ}$

8 0

4 years ago