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scoray [572]
3 years ago
12

Two guitar strings, of equal length and linear density, are tuned such that the second harmonic of the first string has the same

frequency as the third harmonic of the second string. The tension of the first string is 510 N. Calculate the tension of the second string.
Physics
1 answer:
anastassius [24]3 years ago
6 0

Answer:

The tension in the second string is 226.7 N.

Explanation:

Length is L, mass per unit length = m

T = 510 N

Let the tension in the second string is T'.

second harmonic of the first string = third harmonic of the second string

2 f = 3 f'\\\\2\sqrt{\frac{T}{m}} = 3 \sqrt {\frac{T'}{m}}\\\\4 T = 9 T'\\\\4\times 510 = 9 T'\\\\T' = 226.7 N

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A car travels eastwards at 60km/h for 2h, then travels northwards at 20km/h for 8h. Find,
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Answer:

a) Average\ Speed=28\ km/h\\b) Average\ Velocity= 20\ km/h

Explanation:

We\ are\ given\ that,\\Velocity\ of\ the\ car\ Eastwards=60\ km/h\\Time\ taken\ by\ the\ car\ Eastwards=2\ h\\Velocity\ of\ the\ car\ Northwards=20\ km/h\\Time\ taken\ by\ the\ car\ Northwards=8\ h\\Hence,\\As\ we\ know\ that,\\Speed=\frac{Distance}{Time}\\Distance= Speed* Time\\Now,\ lets\ find\ the\ distance\ covered\ by\ the\ car\ in\ both\ the\ cases.

Hence,\\Distance\ Covered\ During\ its\ Eastward\ Journey=60*2=120\ km\\Distance\ Covered\ During\ its\ Northward\ Journey=20*8=160\ km\\Now,\\As\ we\ know\ that\ Average\ Speed=\frac{Total\ Distance}{Total\ Time} \\Here,\\Total\ distance\ of\ the\ car=Distance\ Covered\ During\ its\ Northward\ Journey+Distance\ Covered\ During\ its\ Eastward\ Journey\\Hence,\\Total\ distance\ of\ the\ car=120+160=280\ km\\Total\ time\ taken\ by\ the\ car=8+2=10\ hours\\Hence,\\Average\ Speed\ Of\ the\ Car\ throughout\ its\ journey=\frac{280}{10}=28\ km/h

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3 years ago
A black, totally absorbing piece of cardboard of area a = 2.1 cm2 intercepts light with an intensity of 8.8 w/m2 from a camera s
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Answer:

The value of radiation pressure is 2.933 \times 10^{-8} Pa

Explanation:

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From the formula of radiation pressure in terms of intensity,

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Where P = radiation pressure, c = speed of light

We know value of speed of light,

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Therefore, the value of radiation pressure is 2.933 \times 10^{-8} Pa

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