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Svetach [21]
3 years ago
15

Car decelerates uniformly and comes to a stop after 10 s. The car's average velocity during deceleration was 50 km/h. What was t

he car's deceleration while slowing down?
Help!!!!
Physics
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

a=-1.388\ m/s^2

Explanation:

Initial velocity of car, u = 50 km/h = 13.88 m/s

It stops, v = 0

Time, t = 10 s

We need to find the car's deceleration while slowing down. As the car is slowing down, it will have deceleration. It can be calculated as follows :

a=\dfrac{v-u}{t}\\\\a=\dfrac{0-13.88 }{10}\\\\a=-1.388\ m/s^2

So, the deceleration of the car is 1.388\ m/s^2.

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A light spring stretches 0.13 m when a 0.35 kg mass is hung from it. The mass is pulled down from this equilibrium position an a
Alenkasestr [34]

Answer:

v = 1.30 m/s

Explanation:

given,

mass hung = 0.35 Kg

spring stretched when load is hanged  (x)= 0.13 m

now,

weight of the mass attached = Kx

             m g = k x

             0.35 x 9.8 = k x 0.13

                k = 26.38 N/m

now, using conservation of energy

 \dfrac{1}{2}mv^2 = \dfrac{1}{2}kx'^2

 v = \sqrt{\dfrac{kx'^2}{m}}

 v = \sqrt{\dfrac{26.38 \times 0.15^2}{0.35}}

 v = \sqrt{1.6958}

    v = 1.30 m/s

6 0
3 years ago
A baseball player throws a baseball at a speed of 40 meters per second at an angle of 30 degrees. What is the velocity of projec
Vesna [10]

Answer:

The horizontal component of the velocity is the cosine of 30 degrees multiplied by 40m/s. The cosine of 30 degrees is the 0.8660 . To get the speed, multiply by 40m/s. This equals 34.64, which is approximately 35m/s.

Hope it helpss :)

3 0
2 years ago
Read 2 more answers
Help me please!! 15points
Romashka-Z-Leto [24]

Explanation:

Acceleration is the change in speed over change in time.

a = Δv / Δt

a. The car's acceleration is:

a = (80 km/h − 0 km/h) / 10 s

a = 8 km/h/s

So every second, the speed increases by 8 km/h.

b. The cyclist's acceleration is:

a = (16 m/s − 4.0 m/s) / 5.6 s

a = 2.1 m/s²

c. The stone's speed is:

10.0 m/s² = (v − 0 m/s) / 3.5 s

v = 35 m/s

d. The time is:

1.6 m/s² = (10 m/s − 0 m/s) / t

t = 6.3 s

4 0
3 years ago
A 1 530-kg automobile has a wheel base (the distance between the axles) of 2.70 m. The automobile's center of mass is on the cen
NeTakaya

Answer:

Force on front axle = 6392.85 N

Force on rear axle = 8616.45 N

Explanation:

As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels

Now we know that

F_1 + F_2 = W

F_1 + F_2 = (1530\times 9.81)

F_1 + F_2 = 15009.3 N

now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle

so we can write torque balance about its center of mass

F_1(1.15) = F_2(2.70 - 1.15)

F_1 = 1.35 F_2

now from above equation

F_2 + 1.35F_2 = 15009.3

now we have

F_2 = 6392.85 N

now the other force is given as

F_1 = 8616.45 N

4 0
3 years ago
Assume that a gravitational anomaly in the solar system has shifted a field of asteroids into Earth’s orbit, and the field is no
Mandarinka [93]

Answer:

An asteroid is a minor planet of the inner Solar System. Historically, these terms have been applied to any astronomical object orbiting the Sun.

7 0
2 years ago
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