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Svetach [21]
3 years ago
15

Car decelerates uniformly and comes to a stop after 10 s. The car's average velocity during deceleration was 50 km/h. What was t

he car's deceleration while slowing down?
Help!!!!
Physics
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

a=-1.388\ m/s^2

Explanation:

Initial velocity of car, u = 50 km/h = 13.88 m/s

It stops, v = 0

Time, t = 10 s

We need to find the car's deceleration while slowing down. As the car is slowing down, it will have deceleration. It can be calculated as follows :

a=\dfrac{v-u}{t}\\\\a=\dfrac{0-13.88 }{10}\\\\a=-1.388\ m/s^2

So, the deceleration of the car is 1.388\ m/s^2.

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The driver of a car traveling at 22.8 m/s applies the brakes and undergoes a constant deceleration of 2.95 m/s 2 . How many revo
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Answer:

70 revolutions

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We can start by the time it takes for the driver to come from 22.8m/s to full rest:

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Using the following equation motion we can findout the angle it makes during the deceleration:

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where \omega = 0 m/s is the final angular velocity of the car when it stops, \omega_0 = 114rad/s is the initial angular velocity of the car \alpha = 14.75 rad/s2 is the deceleration of the can, and \Delta \theta is the angular distance traveled, which we care looking for:

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