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frozen [14]
3 years ago
9

Savanna is ordering crafts for Thanksgiving for her class. Each individual craft cost $1.50. There are a shipping fee and handli

ng fee of $10.00 per order. Why are the quantities important?
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

i smell penys

Step-by-step explanation:

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If the sum of seven odd consecutive numbers is 231, find the middle number.
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This is your answer, good luck buddy

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Keith has a package of 75 marbles.He gave an equal number of marbles to each of his 8 friends. How many marbles will be left ove
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9

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The price of a shirt is marked down from $12.50 to $10,00. What is the percent decrease of the shirt?
choli [55]

Answer: 20%.

Step-by-step explanation:

Given, The price of a shirt is marked down from $12.50 to $10.00.

Previous price = $12.50

New price = $10.00

Change in price = Previous price - New price

= $12.50 - $10.00

= $2.50

Now, the percent decrease of the shirt = \dfrac{\text{Change in price}}{\text{Prevoius price}}\times100

=\dfrac{2.50}{12.50}\times100\\\\=20\%

Hence, the percent decrease of the shirt = 20%.

7 0
3 years ago
Bob’s Burger Place made 11 burgers with onions and 7 burgers without onions. What is the ratio of the number of burgers without
Anika [276]

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7:11

Step-by-step explanation:

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Given: PRST is a square
xxTIMURxx [149]

Answer:

(1-\sqrt{2})a^2

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a

Thus,

MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a

Consider isosceles triangle MSC. In this triangle

MS=MC=(\sqrt{2}-1)a.

The area of this triangle is

A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}

Consider right triangle PTS. The area of this triangle is

A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2

5 0
3 years ago
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