Answer:
<em>C. 15</em>
Step-by-step explanation:
Assuming that these segments formed from each parallel line are proportional, x/5 = x-6/3.
Now cross multiply by multiplying each denominator by the opposite numerator, this is so the denominators or bottom numbers of each fraction will cancel.
x/5 = x–6/3 → (3)(x/5) = (3)(x–6/3) → 3x/5 = x–6 →
(5)(3x/5) = (5)(x–6) → 3x = 5(x–6) → 3x = 5x – 30.
The last step is to do the basic algebra to find x:
3x = 5x – 30
–5x –5x
[5x will cancel when you subtract both sides by 5x]
-2x = -30
(-1) (-1)
[2 negatives make a positive when -1 is multiplied by an expression with a negative coefficient]
2x = 30
÷2 ÷2
[divide both sides by 2 to simplify 2x to x]
x = 15
_____
You can also check that both sides are proportional because
5 → x
x = 15
5 → 15
3 → x – 6
x = 15
3 → 9
5 × <u>3</u> = 15
3 × <u>3</u> = 9
Divide 7 by 12
which would give you 0.58
so that’s 58%
Corresponding sides in the triangles MOP and MNQ are
MO and MN,
OP and NQ,
PM and QM.
Ratios of the corresponding sides for similar triangles should be the same.
MQ/MP =MN/MO
MQ/(MQ+QP) = MN/(MN+NO)
5/(5+x) = 6/(6+18/5)
5*(6+18/5)=6(5+x)
30+18 = 30 +6x
18=6x
x=3 =QP
Answer:
<em>AAS</em>
Step-by-step explanation:
<em>because</em><em> </em><em>here </em><em>it </em><em>is </em><em>given</em><em> </em><em>that </em><em>two </em><em>angle </em><em>are</em>
<em> </em><em>equal</em>
and a side is common between both traingle
so, both traingle are congruent by
<em><u>AAS</u></em>
hope it helps
Answer:
d is right...............
