1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
My name is Ann [436]
3 years ago
5

PLESSS ANSWER QUICK I WILL GIVE BRAINLIEST

Mathematics
2 answers:
Lesechka [4]3 years ago
6 0

Answer:

the answer 8/49

Step-by-step explanation:

4/7 divided by 7/2 doesnt go together so the denomintor would be 7/7 then divide 4/2

balandron [24]3 years ago
3 0

Answer:

8 0ver 49

Step-by-step explanation:

You might be interested in
37. Verify Green's theorem in the plane for f (3x2- 8y2) dx + (4y - 6xy) dy, where C is the boundary of the
Nastasia [14]

I'll only look at (37) here, since

• (38) was addressed in 24438105

• (39) was addressed in 24434477

• (40) and (41) were both addressed in 24434541

In both parts, we're considering the line integral

\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy

and I assume <em>C</em> has a positive orientation in both cases

(a) It looks like the region has the curves <em>y</em> = <em>x</em> and <em>y</em> = <em>x</em> ² as its boundary***, so that the interior of <em>C</em> is the set <em>D</em> given by

D = \left\{(x,y) \mid 0\le x\le1 \text{ and }x^2\le y\le x\right\}

• Compute the line integral directly by splitting up <em>C</em> into two component curves,

<em>C₁ </em>: <em>x</em> = <em>t</em> and <em>y</em> = <em>t</em> ² with 0 ≤ <em>t</em> ≤ 1

<em>C₂</em> : <em>x</em> = 1 - <em>t</em> and <em>y</em> = 1 - <em>t</em> with 0 ≤ <em>t</em> ≤ 1

Then

\displaystyle \int_C = \int_{C_1} + \int_{C_2} \\\\ = \int_0^1 \left((3t^2-8t^4)+(4t^2-6t^3)(2t))\right)\,\mathrm dt \\+ \int_0^1 \left((-5(1-t)^2)(-1)+(4(1-t)-6(1-t)^2)(-1)\right)\,\mathrm dt \\\\ = \int_0^1 (7-18t+14t^2+8t^3-20t^4)\,\mathrm dt = \boxed{\frac23}

*** Obviously this interpretation is incorrect if the solution is supposed to be 3/2, so make the appropriate adjustment when you work this out for yourself.

• Compute the same integral using Green's theorem:

\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dy = \iint_D \frac{\partial(4y-6xy)}{\partial x} - \frac{\partial(3x^2-8y^2)}{\partial y}\,\mathrm dx\,\mathrm dy \\\\ = \int_0^1\int_{x^2}^x 10y\,\mathrm dy\,\mathrm dx = \boxed{\frac23}

(b) <em>C</em> is the boundary of the region

D = \left\{(x,y) \mid 0\le x\le 1\text{ and }0\le y\le1-x\right\}

• Compute the line integral directly, splitting up <em>C</em> into 3 components,

<em>C₁</em> : <em>x</em> = <em>t</em> and <em>y</em> = 0 with 0 ≤ <em>t</em> ≤ 1

<em>C₂</em> : <em>x</em> = 1 - <em>t</em> and <em>y</em> = <em>t</em> with 0 ≤ <em>t</em> ≤ 1

<em>C₃</em> : <em>x</em> = 0 and <em>y</em> = 1 - <em>t</em> with 0 ≤ <em>t</em> ≤ 1

Then

\displaystyle \int_C = \int_{C_1} + \int_{C_2} + \int_{C_3} \\\\ = \int_0^1 3t^2\,\mathrm dt + \int_0^1 (11t^2+4t-3)\,\mathrm dt + \int_0^1(4t-4)\,\mathrm dt \\\\ = \int_0^1 (14t^2+8t-7)\,\mathrm dt = \boxed{\frac53}

• Using Green's theorem:

\displaystyle \int_C (3x^2-8y^2)\,\mathrm dx + (4y-6xy)\,\mathrm dx = \int_0^1\int_0^{1-x}10y\,\mathrm dy\,\mathrm dx = \boxed{\frac53}

4 0
3 years ago
14. Find the value of X round the nearest degree 12 15
satela [25.4K]

Answer:

37

Step-by-step explanation:

6 0
3 years ago
Tom's tank hold 12.5
enyata [817]

Answer:

$24.5 = 1 tank

Step-by-step explanation:

All you have to do is multiply.

Since 12.5 gallons = 1 tank,

and $1.96 = 1 gallon

to get the answer, the equation would be,

$1.96*12.5 = 1 tank

$24.5 = 1 tank

Hope it helps!!

7 0
3 years ago
Read 2 more answers
Create your own real-world example of a relation that is a function. Domain: The set of Range: The set of
ivanzaharov [21]

Answer:

C(t)=5000 -10t

Step-by-step explanation:

There are many examples in the real world of relationships that are functions.

For example, imagine a tank full of water with a capacity of 5000 liters, this tank has a small hole, by which 10 liters of water are lost every hour.

If we call C the amount of water in the tank as a function of time, then we can write the following equation for C:

C(t)=C_{0}-at\\

Where:

C (t): Amount of water in the tank as a function of time

C_{0}: Initial amount of water in the tank at time t = 0

a: amount of water lost per hour

t: time in hours

Then the equation is:

C(t)=5000 -10t

The graph of C (t) is a line of negative slope. This relation is a function since for each value of t there is a single value of C.

Its domain is the set of all positive real numbers t between [0,500]

Because the time count starts at t = 0 when the tank is full and ends at t = 500 when empty

Its Range is the set of all positive real numbers C between [0,5000] Because the amount of water in the tank can never be less than zero or greater than 5000Litres

7 0
3 years ago
Read 2 more answers
C=a/5t what does t equal?
-Dominant- [34]
Photo has the answer! hope it helped

8 0
3 years ago
Other questions:
  • Wendy says that soccer balls cost 2 1/2 times as much as baseball cost. do you agree? explain?​
    9·1 answer
  • Witch one is bigger 3/5, 1/2, or 99/100
    12·2 answers
  • PLS I need help with this,
    12·1 answer
  • The graphs of two linear equations are shown.
    6·1 answer
  • Help me please please
    8·2 answers
  • Your friend evaluated an expression using k = 0.5 and p =1/6 and got an answer of 12. Which expression did your friend evaluate?
    12·1 answer
  • A number is divided by
    10·1 answer
  • Matea recorded that water levels in one part of the river fell 1.05 millimeters per year for 2.48 years. Describe how you could
    5·2 answers
  • Expand and simplify (2x^2)(4x+5)-8x(x^2-2)
    6·1 answer
  • Rewrite each of the following expressions without using absolute value bars.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!