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bearhunter [10]
3 years ago
8

Coal gas is produced at a gasworks. Pollutants in the gas are removed by scrubbers, which become less and less efficient as time

goes on. The following measurements, made at the start of each month, show the rate at which pollutants are escaping (in tons/month) in the gas: Time (months) 0 1 2 3 4 5 6 Rate 5 7 9 14 22 31 40 A. Make an overestimate and an underestimate of the total quantity of pollutants that escape during the first month. overestimate
Mathematics
1 answer:
baherus [9]3 years ago
8 0

Answer:

overestimate = 7

underestimate = 5

Step-by-step explanation:

Table

_________________________________

Time (months)    0    1    2     3      4     5     6

Rate                   5   7     9    14    22    31    40

___________________________________

A. Make an overestimate and an underestimate of the total quantity of pollutants that escape during the first month.

Overestimate

For this case, we review the data in the table. The value for first month of total quantity of pollutants that escape is 7. Additionally, we can notice that the rate is increasing.

Just a month and that month has a value of  7

= 1* 7 (The largest value) = 7

Underestimate

This would be equivalent to the total until the previous meassure

= 1*5 = 5

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CAN SOMEONE PLS ANSWER-If W(- 10, 4), X(- 3, - 1) , and Y(- 5, 11) classify AEXY by its sides . Show all work to justify your an
AnnZ [28]

Answer:

  • WX = \sqrt{74} \approx 8.6023253\\\\
  • XY = 2\sqrt{37} \approx 12.1655251\\\\
  • WY = \sqrt{74} \approx 8.6023253\\\\
  • Classify:  Isosceles

============================================================

Explanation:

Apply the distance formula to find the length of segment WX

W = (x1,y1) = (-10,4)

X = (x2,y2) = (-3, -1)

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-10-(-3))^2 + (4-(-1))^2}\\\\d = \sqrt{(-10+3)^2 + (4+1)^2}\\\\d = \sqrt{(-7)^2 + (5)^2}\\\\d = \sqrt{49 + 25}\\\\d = \sqrt{74}\\\\d \approx 8.6023253\\\\

Segment WX is exactly \sqrt{74} units long which approximates to roughly 8.6023253

-------------------

Now let's find the length of segment XY

X = (x1,y1) = (-3, -1)

Y = (x2,y2) = (-5, 11)

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-3-(-5))^2 + (-1-11)^2}\\\\d = \sqrt{(-3+5)^2 + (-1-11)^2}\\\\d = \sqrt{(2)^2 + (-12)^2}\\\\d = \sqrt{4 + 144}\\\\d = \sqrt{148}\\\\d = \sqrt{4*37}\\\\d = \sqrt{4}*\sqrt{37}\\\\d = 2\sqrt{37}\\\\d \approx 12.1655251\\\\

Segment XY is exactly 2\sqrt{37} units long which approximates to 12.1655251

-------------------

Lastly, let's find the length of segment WY

W = (x1,y1) = (-10,4)

Y = (x2,y2) = (-5, 11)

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-10-(-5))^2 + (4-11)^2}\\\\d = \sqrt{(-10+5)^2 + (4-11)^2}\\\\d = \sqrt{(-5)^2 + (-7)^2}\\\\d = \sqrt{25 + 49}\\\\d = \sqrt{74}\\\\d \approx 8.6023253\\\\

We see that segment WY is the same length as WX.

Because we have exactly two sides of the same length, this means triangle WXY is isosceles.

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