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3 years ago

Which of the following point-slope form equations could be produced with the points (4, -5) and (-4, -3)?

Mathematics

1 answer:

Alexus [3.1K]3 years ago

6 0

Answer:

$y + 5 =- \frac{1}{4} (x-4)$

Step-by-step explanation:

You will find the slope-intercept form first, and then you can find the point slope form of the equation

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ra1l [238]

Step-by-step explanation:

if n=5

5-10+9(5)-3

-5+45-3

45-8=37

if n=-9

-9-10+9( -9)-3

-19-81-3=-103

5 0

3 years ago

Click on the graph below to create a quadrilateral with vertices at the following points. (-4,9), (-8,9), (-9,7), (-9, 4)

Shalnov [3]

Given (-4,9) (-8,9),(-9,7,(-9,4)

...

To Find : plot the point and draw quadrilateral

Solution:

(-4,9)

go 4 left of origin and then go 9 up

(-8,9)

go 8 left of origin and then go 8 up

(-9,7)

go 9 left of origin and then go 7 up

(-9,4)

go 9 left of origin and then go join (-4,9) with (-8,9) and (-9,4) 4 up

join (-9,7) with (-8,9) and (-9,4)

Quadrilateral is constructed

4 0

2 years ago

Help will give brainliest

horrorfan [7]

Answer:

Step-by-step explanation:

i don’t have time now but i promise i’ll give it when i have time

7 0

3 years ago

Read 2 more answers

Alyssa read 25 pages of a new book the first day she bought it. After the first day, she read 5 pages a day. If the book was 350

Ostrovityanka [42]

Answer:

5x + 25

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find me equation of the circle with Center at ( 3, - 2) and radius of 3

blondinia [14]

The equation of a circle with center $(x_0,y_0)$ and radius $r$ is

$(x-x_0)^2+(y-y_0)^2=r^2$

In your case,

$x_0=3,\quad y_0=-2,\quad r=3$

Plug these values into the generic formula and you'll get your equation.

5 0

3 years ago