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Vaselesa [24]
3 years ago
12

Use the following situation to answer the questions that follow: A ball is thrown up in the air, and it's height (in feet) as a

function of time (in seconds) can be written as h(t) = -16t2 + 32t + 6.
Describe in detail (using formulas and/or specific steps needed) TWO ways to find the maximum height reached by the ball.
Mathematics
1 answer:
alexandr1967 [171]3 years ago
6 0

Answer:

1) find the verted of the parabols

[-b/2a, f(-b/2a)]

-32/-32 = 1  .... -16+32+6 = 22

2) take the derivative and set = to 0

-32t+32 = 0

t = 1 .....height = 22

Step-by-step explanation:

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Natasha2012 [34]

Answer:

g(9) = 48

Step-by-step explanation:

g(x)= – x2–5x + 12

<u>I'll assume this is </u>

<u>g(x)= – x^2–5x + 12</u>

find g(9)

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3 years ago
PLS HELP ME ASAP FOR 10 and 11 (MUST SHOW WORK!!!) + LOTS OF POINTS!!
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Problem 10:
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The first part of our expression is: g =
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Step-by-step explanation:

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