Given that B is the midpoint of line AC and line BC is congruent to line DE.
The following statements and reasons, proves that line AB is congruent to line DE.
Statement Reasons
1. B is the midpoint of line AC Given
2. Line AB is congruent to line BC. Midpoint of a line segment
3. Line BC is congruent to line DE Given
4. Line AB is congruent to line DE Transitive property
So,
First, we find the prime factored form (P.F.F.) of 65 and 91.
P.F.F. of 65: 5 * 13
P.F.F. of 91: 7 * 13
Find the common numbers
13
13 = G.C.F.
Note: This method works for finding any G.C.F. (find common primes)
If f(z)=m^z - n^z <span>and f(1)=2, f(2)=8
then
m - n = 2 so m = n + 2
m^2 - n^2 = 8
substitute </span>m = n + 2 into m^2 - n^2 = 8
so
m^2 - n^2 = 8
(n + 2)^2 - n^2 = 8
n^2 + 4n + 4 - n^2 = 8
4n = 4
n = 1
m = n + 2 = 1 + 2 = 3
so f(z) = 3^z - 1^z
if z = 1 the f(1) = 3^1 - 1^1 = 2
if z = 2 the f(2) = 3^2 - 1^2 = 9 - 1 = 8
if z = 3 the f(3) = 3^3 - 1^2 = 27 - 1 = 26
answer
f(3) = 26
(820*7)-(480*7)=? This is how to solve the equation
