Answer:
Cost to construct the road = 775000 rupees
Step-by-step explanation:
Square field has a side = 150 m
Area of the field = (Side)²
= (150)²
= 22500 m²
Length of the park with road around the field = 150 + 2×(width of the road)
= 150 + (2×5)
= 160 m
Similarly, width of the park with road around the field = 160 m
Area of the park with road = (Side)²
= (160)²
= 25600 m²
Area of road = Area of the park with road - Area of the park
= 25600 - 22500
= 3100 m²
Since, cost of constructing the road = 250 rupees per square meter
Cost to construct the road with the given area = 250 × 3100
= 775000 rupees
Yes, ik what a pie is but which definition of a pie are you talking about. A food or mathematical?
Answer: A. A=(1000-2w)*w B. 250 feet
C. 125 000 square feet
Step-by-step explanation:
The area of rectangular is A=l*w (1)
From another hand the length of the fence is 2*w+l=1000 (2)
L is not multiplied by 2, because the opposite side of the l is the barn,- we don't need in fence on that side.
Express l from (2):
l=1000-2w
Substitude l in (1) by 1000-2w
A=(1000-2w)*w (3) ( Part A. is done !)
Part B.
To find the width w (Wmax) that corresponds to max of area A we have to dind the roots of equation (1000-2w)w=0 ( we get it from (3))
w1=0 1000-2*w2=0
w2=500
Wmax= (w1+w2)/2=(0+500)/2=250 feet
The width that maximize area A is Wmax=250 feet
Part C. Using (3) and the value of Wmax=250 we can write the following:
A(Wmax)=250*(1000-2*250)=250*500=125 000 square feets
