a-7=3(b+2)
1. Simplify/Combine like terms
a-7=3b+6
2. Remove a variable
a-7-a=3b+6-a
7=2b+6
3. Isolate the variable
7-6=2b-6
1=2b
4. Divide
1/2=2b/2
b=1/2
1/2g?
Answer:
least possible number of sweets = lowest common multiple of 5,6 & 10 - 2
-I hope this helps! I got it figured out until near like the very end.-
-Please mark as brainliest!- Thanks!
The answer would be D, because you do 4200÷56=75 minutes. 75 minutes= 1 hour and 15 minutes
92 students were on the bus and half left
so thats 92/2 and you get 46
46 students were left on the bus
Hope this helps! :))
Answer:
<em>n</em> - <em>k</em> + 1
Step-by-step explanation:
This is assuming (because you did not say) that <em>n</em> and <em>k</em> are integers and <em>n</em> is greater than <em>k</em>.
Example: from 2 to 5 {2, 3, 4, 5} includes 5 - 2 + 1 = 4 numbers.
Example: from -6 to 4 includes 4 - (-6) + 1 = 11 numbers, namely {-6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4}