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2 years ago

15

Use the drawing tool(s) to form the correct answers on the provided graph.

2 answers:

Veronika [31]2 years ago

6 0

Answer:

(See attachment below)

Step-by-step explanation:

The following information is derived from the graphic:

X-Intercepts: (-3,0), (1,0)

Y-Intercepts: (0,-3)

Vertex: (-1,-4)

Axis of symmetry of the function: x = -1

anastassius [24]2 years ago

4 0

Answer:

See below in bold.

Step-by-step explanation:

This is the vertex form of a parabola which opens upwards.

To find the x intercept put h(x) = 0:

(x + 1)^2 - 4 = 0

(x + 1)^2 = 4

x + 1 = +/- 2

x = (-3, 0) an (1, 0) are the x-intercepts.

For the y-intercept we put x = 0

y = (0+1)^2 - 4 = -3

y-intercept = (0, -3).

The vertex is (-1, -4).

Axis of symmetry is x = -1.

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When it says graph the image, it's asking me to graph a reflection across x = -2. what's the answer look like?

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The reflection across x = -2 will be x = 2.

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2 years ago

John has taken out a loan for college. He started paying off the loan with a first payment of $100. Each month he pays, he wants

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2 years ago

100 POINTS!!! PLEASE I NEED HELP DUE TODAY!!!!

Volgvan

Using weighed averages, it is found that:

The final grade is 91.
The final grade is 66.8.
The higher grade would be 79.55, with the second grading scheme.
On average, she sold $48,280 per day.
On average, she makes $12.5 per hour.

---------------------------------------

To find the weighed average, we multiply each value by it's weight.

---------------------------------------

Question 1:

Grade of 91, with a weight of 67%.
Grade of 91, with a weight of 33%.

Thus:

$F = 91\times0.67 + 91\times0.33 = 91$

The final grade is 91.

---------------------------------------

Question 2:

Grade of 83, with a weight of 40%(highest grade).
Grade of 60, with a weight of 30%.
Grade of 52, with a weight of 30%.

Thus:

$F = 83\times0.4 + 60\times0.3 + 52\times0.3 = 66.8$

The final grade is 66.8.

---------------------------------------

Question 3:

With teacher 1:

75 with a weight of 25%.
80 with a weight of 10%.
85 with a weight of 40%.
62 with a grade of 25%.

Thus:

$F_1 = 75\times0.25 + 80\times0.1 + 85\times0.4 + 62\times0.25 = 76.25$

---------------------------------------

With teacher 2:

75 with a weight of 15%.
80 with a weight of 10%.
85 with a weight of 60%.
62 with a weight of 15%.

Thus:

$F_2 = 75\times0.15 + 80\times0.1 + 85\times0.6 + 62\times0.15 = 79.55$

The higher grade would be 79.55, with the second grading scheme.

---------------------------------------

Question 4:

Average of $36,432, with a weight of $\frac{3}{3+10} = \frac{3}{13}$
Average of $51,834, with a weight of $\frac{10}{13}$

Thus:

$A = 36432\frac{3}{13} + 51834\frac{10}{13} = \frac{36432\times3 + 51834\times10}{13} = 48280$

On average, she sold $48,280 per day.

---------------------------------------

Question 5:

Average of $14.84, with a weight of $\frac{6}{6+8} = \frac{6}{14} = \frac{3}{7}$
Average of $10.76, with a weight of $\frac{4}{7}$

Thus:

$A = 14.84\frac{3}{7} + 10.76\frac{4}{7} = \frac{14.84\times3 + 10.76\times4}{7} = 12.5$

On average, she makes $12.5 per hour.

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