3 years ago

Divide (x^3+2x-6x-9) by (x+3)

Mathematics

1 answer:

GenaCL600 [577]3 years ago

7 0

Answer:

x² - 3x + 5 - [24÷(x+3)]

Step-by-step explanation:

1. Expand (x³ + 2x - 6x - 9)

= x³ - 4x - 9

2. Divide [x³ - 4x - 9 by x+3]

= x² + [(-3x^2-4x-9) ÷ (x+3)]

3. Divide [(-3x^2-4x-9) by (x+3)]

= -3x + [(5x-9) ÷ (x+3)]

x² - 3x + [(5x-9) ÷ (x+3)]

4. Divide [(5x-9) ÷ (x+3)]

= 5 + [(-24) ÷ (x+3)]

x² - 3x + 5 + [(-24) ÷ (x+3)]

= x² - 3x + 5 - [24 ÷ (x+3)]

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