All categories

3 years ago

A Company increased the number of its employees from 340 to 425. Find the percent increase.

1 answer:

8 0

25%

Because You must do the original number by the new.

so, 425-340= 85

but ur not done now,

divide that 85 by the original number then times by 100!

85/340= .25*100= 25%

and ur done hope this helped

You might be interested in

Simplify the expression 8h - 57-3m by adding or subtracting the like term

tigry1 [53]

Answer:

You cannot simplify this expression.

Step-by-step explanation:

There are no like terms, meaning this is as simplified as it can get

4 0

3 years ago

Read 2 more answers

Suppose the probability that it rains in the next two days 1/3 for tomorrow and 1/6"for the day after tomorrow. What is P(rain t

Zigmanuir [339]

This events are separate , so the probability of both of which combined is the product of them.

Let P(A) rain tomorrow event
P(B) rain after tomorrow event

P(A) = 1/3

P(B) = 1/6

P(A in B) = P(A) * P(B) = 1/3 * 1/6= 1/18

Choice: (B)

7 0

4 years ago

Read 2 more answers

Help please just look at the picture it has the question and answer choices

ratelena [41]

C is ur answer............

6 0

3 years ago

Solve using square roots 3x^2+25=73

seropon [69]

Heya !

Given expression -

$3 {x}^{2} + 25 = 73$

Subtracting 25 both sides ,

$3 {x}^{2} + 25 - 25 = 73 - 25 \\ \\ 3 {x}^{2} = 48$

Dividing by 3 on both sides ,

$\frac{3 {x}^{2} }{3} = \frac{48}{3} \\ \\ {x}^{2} = 16$

Therefore ,
$x = + \: 4 \: \: \: \: or \: \: - 4 \: \: \: \: \: \: \: Ans.$

4 0

4 years ago

When a truckload of apples arrives at a packing plant, a random sample of 125 apples are selected and examined for bruises and o

valentinak56 [21]

Answer:

You would need to go 1.6 standard errors away from 0.09.

Step-by-step explanation:

We can solve this using the normal distribution, because, by the Central Limit Theorem, the sampling distribution of the sample proportions is approximately normal.

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

89% of the sample proportions.

50 - 89/2 = 5.5th percentile

50 + 89/2 = 94.5th percentile

5.5th percentile

X when Z has a pvalue of 0.055. So X when Z = -1.6.

So 1.6 standard error away from 0.09.

94.5th percentile

X when Z has a pvalue of 0.945. So X when Z = 1.6.

So 1.6 standard error away from 0.09.

You would need to go 1.6 standard errors away from 0.09.

3 0

4 years ago