Answer:
See below.
Step-by-step explanation:
By definition the median of the triangle bisects the base of the isosceles triangle.
We need to prove that the 2 triangles formed by the median are congruent.
If the 2 triangles are ABD and ACD where BD is the median and < ABC is the angle from which BD is drawn.
BD = BD ( the common side)
AD = DC ( because BD is the median).
AB = AC ( because ABC is an isosceles triangle).
So Triangles ABD and ACD are congruent by SSS.
Therefore m < ABD = m < CBD, so BD is the bisector of < ABC.
To prove BD is also the altitude:
Triangles ABD and CBD are congruent as we have just proven. Therefore the
of measure of the base angle ABD = m < CBD . Also they are adjacent angles ( on the same line) so they add up to 180.
Therefore angles ABD and CBD are both right angles and BD is the altitude of triangle ABC.
I'm not gonna give the answer because you have to solve it. Sorry. But I'll help you get it.
Step 1: solve the equation for each angle
Step 2: Add the totals from each angle
Step 3: Divide the total by 360
Step 4: You got your answer
I hope this helped! I'm sorry I answered really late.
Given:
The area model for
.
To find:
The value of
and the missing values in the area model.
Solution:
2.1 can be written as 2 and 0.1 on the left side of the area model.
3.2 can be written as 3 and 0.2 on the top of area model.
Area of the four parts of the area model are:
![2\times 3=6](https://tex.z-dn.net/?f=2%5Ctimes%203%3D6)
![2\times 0.2=0.4](https://tex.z-dn.net/?f=2%5Ctimes%200.2%3D0.4)
![0.1\times 3=0.3](https://tex.z-dn.net/?f=0.1%5Ctimes%203%3D0.3)
![0.1\times 0.2=0.02](https://tex.z-dn.net/?f=0.1%5Ctimes%200.2%3D0.02)
The complete area model is shown below.
After adding all areas of the area model, we get
![6+0.4+0.3+0.02=6.72](https://tex.z-dn.net/?f=6%2B0.4%2B0.3%2B0.02%3D6.72)
Therefore, the value of
is 6.72 and the missing values of the area model are 0.3 and 0.02 respectively.
Answer:
Step-by-step explanation:
Given that a popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams.
i.e. Sample mean = 1040 and
Sample std dev s = 25 gm
Sample size n = 100
Hence by central limit theorem we have the sample mean follows a normal distribution with mean =1040 and std dev = s = 25 gm
![\bar X = N(1040,25)](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20N%281040%2C25%29)
Normal curve would be with mean 1040 and std deviatin 25
b) P(X>1115)
= 1-0.9987
=0.0013
i.e. 0.13% would receive a bag that had a weight greater than 1115 grams
Answer:
A perpendicular bisector of a line segment is a line segment perpendicular to and passing through the midpoint of (left figure). The perpendicular bisector of a line segment can be constructed using a compass by drawing circles centered at and with radius and connecting their two intersections.