9514 1404 393
Answer:
DE = 86
EF = 84
Step-by-step explanation:
We assume that point E lies on segment DF, so that ...
DE + EF = DF
(3x +20) +(2x +40) = 170
5x = 110 . . . . . . . . . . . . . . . collect terms, subtract 60
x = 22 . . . . . . . . . . . . divide by 5
DE = 3×22 +20 = 66 +20 = 86
EF = 2×22 +40 = 44 +40 = 84
<span>You will need to weight those balls only twice.
You weight 6 balls, 3 on one side of weight and 3 on another, and other
3 balls you have are in your hand.
Check picture bellow</span>
Answer:
y = 6 or 8
Step-by-step explanation:
1. Subtract the constant:
y^2 -14y = -48
2. Add the square of half the y-coefficient:
y^2 -14y +49 = -48 +49
Write as a square, if you like:
(y -7)^2 = 1
3. Take the square root:
y -7 = ±√1 = ±1
4. Add the opposite of the constant on the left:
y = 7 ±1 = 6 or 8
The solution is y = 6 or y = 8.
Answer:
Δ AXY is not inscribed in circle with center A.
Step-by-step explanation:
Given: A circle with center A
To find: Is Δ AXY inscribed in circle or not
A figure 1 is inscribed in another figure 2 if all vertex of figure 1 is on the boundary of figure 2.
Here figure 1 is Δ AXY with vertices A , X and Y
And figure 2 is Circle.
Clearly from figure, Vertices A , X and Y are not on the arc/boundary of circle.
Therefore, Δ AXY is not inscribed in circle with center A.
Answer:
x = 0
y = -12
Step-by-step explanation:
Plug in what y is equal to into the second equation
-3(x - 12) = 2x + 36
Distribute the -3
-3x + 36 = 2x + 36
-36 -36
-3x = 2x
They cannot be equal so x = 0
Plug in 0 into the y equation
y = 0 - 12
y = -12
