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Ivan
3 years ago
8

From the set 1/2/3/4/5 which values make the inequality n + 1 > true?

Mathematics
1 answer:
saul85 [17]3 years ago
7 0

Hi there!

To make n+1>4 true, you must have n be a numebr greater than 3...

The reason why is because if it is less than 3 or 3, it’ll have to be <.

The two numbers that can make this equation true is 4 and 5...

4+1=5>4

5+1=6>4

And if it is 1,2, and 3 it would be:

1+1=2

2+1=3

3+1=4=4

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For triangle ABC, find the measure of AB given me∠ A = 55 degrees, m∠b= 44 degrees, and b=6. . A. 45.22. B.96.68. C.88.19. .
jekas [21]
There exist a similar question where b = 68 instead of 6. First, determine the measure of the third angle, angle C,
                               m∠c = 180 - (55° + 44°) = 81°
Let x be the side AB, that which is opposite to angle C. Through the Sine Law,
                                  68 / sin 44° = x / sin 81°
From the equation, the value of x is equal to 96.68. Thus, the answer is letter B. 
4 0
3 years ago
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Let us consider a sequence <img src="https://tex.z-dn.net/?f=%5Crm%20a_%7Bn%7D" id="TexFormula1" title="\rm a_{n}" alt="\rm a_{n
kirill115 [55]

Hi there,

a_{5}=2850

Please check the attached image for answer.

<em>Hope </em><em>it </em><em>helps </em><em>.</em><em>.</em><em>.</em>

5 0
2 years ago
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How are these identical??
Karolina [17]
Cuz They Are Identical Duhhh
8 0
3 years ago
PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS
Reil [10]

Given

x+1 = \sqrt{7x+15}

We have to set the restraint

x+1\geq 0 \iff x \geq -1

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}

So, we have to impose

x-7\geq 0 \iff x \geq 7

Squaring both sides, we have

(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0
3 years ago
Willing to give brainliest! Practice question I dont understand the math.
aivan3 [116]

Answer:

Step-by-step explanation:

Part A:

The interquartile range is approximately 10

Part B:

The difference between the median values for each data set  is approximately 6

Part C:

i) More widely distributed and concentrated to the beginning of the month

The better measure of the center for the male dataset is the median

ii) The skewed distribution

The mean is the better measure of center for the dataset

Part D;

A possible reason for the outlier is by chance

4 0
3 years ago
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