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11Alexandr11 [23.1K]
3 years ago
9

Will get brainliest.

Chemistry
1 answer:
yaroslaw [1]3 years ago
5 0

Answer:

1.00 g

Explanation:

got it on pex

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Which of the following is true concerning the reaction below?
levacccp [35]
Right answer is option d that o is oxidized.
5 0
3 years ago
Read 2 more answers
F2 + 2HCl + Cl2 + 2HF I need help what are the answers to these questions?
Anon25 [30]

In the given reaction  fluorine is reduced and chlorine is oxidized.

<h3>What is oxidation and reduction?</h3>

Oxidation is a process in which addition of oxygen or removal of hydrogen and electron takes place, while reduction is a process in which addition of hydrogen & electrons or removal of oxygen takes place.

Given chemical reaction is:

F₂ + 2HCl → Cl₂ + 2HF

  • In the above reaction fluorine is reduced as it accepts an electron and increase in it its oxidation state takes from 0 to -1, which shows reduction.
  • In the reaction chlorine is oxidized as it losses an electron and decrease in its oxidation state takes from -1 to 0, which shows oxidation.
  • Oxidation half reaction is:

F₂ + 2e⁻ → 2F⁻

  • Reduction half reaction is:

2Cl⁻ → Cl₂ + 2e⁻

Hence, fluorine is reduced and chlorine is oxidized in the given reaction.

To know more about oxidation & reduction, visit the below link:

brainly.com/question/4222605

#SPJ1

5 0
2 years ago
The reaction ag+(aq) + cl−(aq) ↔ agcl(s) has an equilibrium of 1020 (keq = 1020). if you have a beaker containing 1 liter of wat
lord [1]
When Q is equal the initial concentration of the products / the initial concentration of the reactants. 

so, Q = [Ag]*[Cl-]  and we neglected [AgCl] as it is solid

∴ Q = 10^-6 * 10^-5 

       = 10^-11 

now we will compare the value of Q with the value of Keq:

when Q = Keq so, the system is in equilibrium

and when Q > Keq so, the reaction will go forward (shift to right) to achieve equilibrium.

and when Q< Keq so, the reaction will go left (shift to left) to achieve equilibrium.

when Q = 10^-11 and Keq = 10^20

∴Q< Keq 

and the reaction will shift to left.
3 0
3 years ago
Explain the differences in boiling point of a 1-pentene (bp 30°c), 1-bromopentane (bp 129°c) and 1-pentanol (bp 137°c). what int
Natali [406]
Generally bonds present between molecules are called intermolecular forces. they are three types:
1) Wander Wall forces (London forces)
2) Dipole - dipole interaction.
3) Hydrogen bond.
- As molecular weight increases boiling point also increases due to surface are is directly proportional to Wander Waal forces.
- Dipole-dipole attraction: the attraction between two different polarizable molecules is called dipole- dipole attraction, this attraction play important role in boiling point.
- Hydrogen bond: electrostatic attraction between hydrogen and more electronegative atom is called hydrogen bond.
- The substance which has hydrogen bond have higher boiling point.
1-pentanol has hydrogen bond
1- Bromopentane has dipole - dipole
1-pentene has only London forces
Hydrogen bond > dipole - dipole attraction > London force 
4 0
3 years ago
What is the theoretical yield of H2O if 160 g of H2O is produced from 18 g of H2 and an excess of O2?
Sav [38]

Answer:

Explanation: The theoretical yield of H2O if 130g of H2O is produced from 18g of H2 and an excess of O2 is 160g.

4 0
3 years ago
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