3. How does heat travel by conduction?
2 answers:
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Answer:
The temperature at which the liquid vapor pressure will be 0.2 atm = 167.22 °C
Explanation:
Here we make use of the Clausius-Clapeyron equation;
Where:
P₁ = 1 atm =The substance vapor pressure at temperature T₁ = 282°C = 555.15 K
P₂ = 0.2 atm = The substance vapor pressure at temperature T₂
= The heat of vaporization = 28.5 kJ/mol
R = The universal gas constant = 8.314 J/K·mol
Plugging in the above values in the Clausius-Clapeyron equation, we have;
T₂ = 440.37 K
To convert to Celsius degree temperature, we subtract 273.15 as follows
T₂ in °C = 440.37 - 273.15 = 167.22 °C
Therefore, the temperature at which the liquid vapor pressure will be 0.2 atm = 167.22 °C.
The value of pka for in an aqueous solution is 9.2.
Kb denotes the base dissociation constant.
pKa + pKb =14 at 25 degree celcius.
pKa + 4.8 =14
pKa = 9.2
pKb is the negative base-10 logarithm of the base dissociation constant (Kb) of a solution.
It is used to determine the strength of a base or alkaline solution.
The value of pka for in an aqueous solution is 9.2.
Learn more about pka here:
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