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4 years ago

Which will reduce the possible environmental damage associated with mining uranium

Chemistry

2 answers:

jeyben [28]4 years ago

6 0

Increasing the reprocessing of used fuel for reuse

Volgvan4 years ago

5 0

Answer:

B. increasing the reprocessing of used fuel for reuse

Explanation:

I took the test.

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How many moles of ammonium nitrate are there in 32.5 mL of<br> a0.125 M NH4NO3 solution?

Nady [450]

<u>Answer:</u> The number of moles of ammonium nitrate is 0.004 moles.

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

We are given:

Molarity of $NH_4NO_3$ solution = 0.125 M

Volume of solution = 32.5 mL

Putting values in above equation, we get:

$0.125M=\frac{\text{Moles of }NH_4NO_3\times 1000}{32.5mL}\\\\\text{Moles of }NH_4NO_3=0.004mol$

Hence, the number of moles of ammonium nitrate is 0.004 moles.

8 0

3 years ago

what is the molar mass of nicotine (C10H14N2)? Question 6 options: 14.11 g/mol 28.02 g/mol C 120.1 g/mol 162.2 g/mol C

viva [34]

Answer:

162.2 g/mol

Explanation:

Molar mass is defined as the mass in 1 mole of the substance. It is calculated by adding the molar mass of the substituents each multiplied by the subscript they have in the formula.

Thus, To calculate molar mass of nicotine having formula, $C_{10}H_{14}N_2$

Molar mass of C = 12.0107 g/mol

Molar mass of H = 1.00784 g/mol

Molar mass of N = 14.0067 g/mol

Thus, molar mass of nicotine = $12.0107\times 10+1.00784\times 14+14.0067\times 2$ = 162.2 g/mol

6 0

4 years ago

Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical equation: ()zn

Bingel [31]

Based on the chemical equation, to balance the equation we use 2 as a coefficients of HCl on left hand side of reaction.

<h3>What is balanced equation?</h3>

Balanced chemical equations are those equation in which each entities are present in same amount on left side as well as on the right side of the chemical reaction.

Given chemical reaction is:

Zn + HCl → ZnCl₂ + H₂

Above reaction is not balanced equation as number of chlorine and hydrogen atoms are not same, so balanced equation will be:

Zn + 2HCl → ZnCl₂ + H₂

Hence we add 2 as a coefficient of HCl to balance the equation.

To know more about balance equation, visit the below link:
brainly.com/question/26694427

8 0

2 years ago

Chemical Reactions Unit Test

dusya [7]

The right side of the equation yields 3CO₂+6H₂O molecules if the 2 in front of 2O is changed to a 3.

The correct option is A.

<h3>What are molecules ?</h3>

The smallest identifiable unit into which a pure substance can be divided while still retaining its composition and chemical properties is called a molecule.

<h3>Briefing:</h3>

Given the chemical equation expressed as:

CH₄+2O₂ → CO₂ + 2H₂O

According to the equation, 1 mole of methane and 2 moles of oxygen combine to create 1 mole of carbon dioxide and 2 moles of water.

The right equation will be written as: If 3 moles of oxygen are used in place of the original amount of moles of oxygen.

3CH₄+2(3O₂) → 3CO₂ + 6H₂O

This shows that the right side of the equation will result in 3CO₂+6H₂O if the 2 in front of 2O is changed to a 3.

To know more about Molecules visit:

brainly.com/question/19556990

#SPJ13

The complete question is -

Use the equation to answer the question.

CH₄+2O₂ → CO₂ + 2H₂O

If you change the 2 in front of 2O₂ to a 3, what will be the change in the results on the right side of the equation?

A- There are now 3CO₂+6H₂O. molecules.

B- There is an extra O₂ molecule left over.

C- Nothing changes in the equation.

D- There are now 3H₂O molecules.

3 0

1 year ago

How many grams of cuno3 will be required to make 1.00 l of 0.420 m solution?

7nadin3 [17]

Answer:

The answer to your question is: 52.92 g of CuNO₃

Explanation:

Data

grams of CuNO₃ = ?

volume = 1 l

concentration = 0.420 M

MW of CuNO₃ = 64 + 14 + 3(16) = 126 g

Formula

Molarity = moles / volume

moles = Molarity x volume

moles = 0.420 x 1

moles = 0.420 moles

1 mol of CuNO₃ ------------------- 126 g of CuNO₃

0.420 moles CuNO₃ ------------- x

x = (0.420 x 126) / 1

x = 52.92 g of CuNO₃

3 0

3 years ago