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bekas [8.4K]
3 years ago
13

{[(3x2)+(5+4)x2]-3}x3=

Mathematics
1 answer:
madreJ [45]3 years ago
8 0

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "x3"   was replaced by   "x^3".  2 more similar replacement(s).

((3•(x2))+(9•(x2)))-3x3

((3 • (x2)) +  32x2) -  3x3

(3x2 +  32x2) -  3x3

Pull out like factors :

12x2 - 3x3  =   -3x2 • (x - 4)

-3x^2 • (x - 4)

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2. Starting at noon, the temperature dropped steadily at a rate of 0.3 degrees Celsius
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Step-by-step explanation:

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2 years ago
Assume that women have heights that are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches.
Maurinko [17]

Answer:

Q3 = 65.7825.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 63.6, \sigma = 2.5

Find the value of the quartile Q3. (Hint: Q3 has an area of 0.75 to its left.)

This is the value of X when Z has a pvalue of 0.75. So it is X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 63.6}{2.5}

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3 years ago
Which does not represent an equivalent expression to 8x +4
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d) 2x(4x + 2)

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4 0
2 years ago
Consider the differential equation: xy′(x2+7)y=cos(x)+e3xy. Put the differential equation into the form: y′+p(x)y=g(x), determin
icang [17]

Answer:

Linear and non-homogeneous.

Step-by-step explanation:

We are given that

\frac{xy'}{(x^2+7)y}=cosx+\frac{e^{3x}}{y}

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).

We have also find type of differential equation.

y'=\frac{(x^2+7)y}{x}(cosx+\frac{e^{3x}}{y}}

y'=\frac{(x^2+7)cosx}{x}y+\frac{(x^2+7)e^{3x}}{x}

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It is linear differential equation because  this equation is of the form

y'+P(x)y=g(x)

Compare it with first order first degree linear differential equation

y'+P(x)y=g(x)

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\frac{dy}{dx}=\frac{(x^2+7)(ycosx+e^{3x})}{x}

Homogeneous equation

\frac{dy}{dx}=\frac{f(x,y)}{g(x,y)}

Degree of f and g are same.

f(x,y)=(x^2+7)(ycosx+e^{3x}),g(x,y)=x

Degree of f and g are not same .

Therefore, it is non- homogeneous .

Linear and non-homogeneous.

3 0
3 years ago
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