Answer:
We need to find the circumference, and in order to find the circumference we must know the formula for it.
Formula for circumference of a circle;
a = 2πr
Where π is the pi(3.14 or 22/7), and r is the radius which is half of the diameter.
Since we are given the diameter, we need to find the radius. So 1/2 of the diameter (26 x 1/2) = is 13
Now we just plug in the actual values in the formula:
a = 2πr
a = 2 x 3.14 x 13
a = <u>18.84 feet</u>
But now, we need to find how many revolutions it would take to get to 500 feet.
So we divide 500 feet by 18.84 feet;
500/18.84 = 26.53, around 27 revolutions.
Step-by-step explanation:
4x² + 11x - 3 = 0
(4x-1)(x+3) = 0
x = 1/4, -3
The distance flown by plane is 750 kilometers.
Step-by-step explanation:
Let,
Distance traveled by plane = x
Distance traveled by car = y
Total distance = x+y
According to given statement;
The distance by car was 125 kilometers less than the distance by plane.
y = x - 125 => x=y+125 Eqn 1
The total distance was 500 kilometers less than three times the distance traveled by car.
Total distance = 3y - 500
x+y=3y-500 Eqn 2
Putting value of x from Eqn 1;

Putting y=625 in Eqn 1

The distance flown by plane is 750 kilometers.
Keywords: linear equations, substitution method
Learn more about linear equations at:
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Answer:

Step-by-step explanation:


