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spayn [35]
3 years ago
8

Find the equation of the line which passes through (-2,-2) and (2, -4).

Mathematics
2 answers:
Lana71 [14]3 years ago
8 0
It should be B

Calculate the slopes using the change of y over the change in x

-2/2=-1

That’s the only option with a slope of -1
Lynna [10]3 years ago
8 0
It is B y =-X- 3 hope that helps
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Solve.<br><br> one-thirds – 6 &lt; 24
GREYUIT [131]

Answer:

90

Step-by-step explanation:

6 0
3 years ago
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write the restrictions that should be imposed on the variable for each of the following function. then find, explicitly, the dom
matrenka [14]

By using the rules that the value inside square root can’t be negative and the denominator value can’t be zero, the domain for the given function is a) x<-1 and x>1  b) p≤1/2  c) s>-1.

I found the complete question on Chegg, here is the full question:

Write the restrictions that should be imposed on the variable for each of the following function. Then find, explicitly, the domain for each function and write it in the interval notation a) f(x)=(x-2)/(x-1)  b) g(p)=√(1-2p)  c) m(s)= (s^2+4s+4)/√(s+1)

Ans. We know that a number is not divisible by zero and number inside a square root can not be negative. In both the cases the outcome will be imaginary.

a) For this case the denominator x-1 can not be zero. So, x ≠1 and the domain is x<-1 and x>1.

b) For this case the value inside square root can’t be negative. So, p can’t be greater than 1/2 the domain is p≤1/2.

c) For this case also the value inside square root can’t be negative and the denominator value can’t be zero. So, s can’t equal or less than -1 and domain is s>-1.

Learn more about square root here:

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3 0
2 years ago
3) g(n) = 2n<br> h(n) = n² + 5<br> Find (g + h)(n)
elena55 [62]
(g + h)(n) =
g(n) + h(n) =
2n + n^2 + 5 =
n^2 + 2n + 5 (standard form)
6 0
3 years ago
Write the following series in sigma notation.<br> 7 + 16 + 25 +34 +43 +52 + 61
Solnce55 [7]

The series 7 + 16 + 25 +34 +43 +52 + 61 is an illusration of arithmetic series

The sigma notation of the series is: \sum\limits^7_{n=1} {9n - 2}

<h3>How to write the series in sigma notation?</h3>

The series is given as:

7 + 16 + 25 +34 +43 +52 + 61

The above series is an arithmetic series, with the following parameters

  • First term, a = 7
  • Common difference, d = 9
  • Number of terms, n = 7

Start by calculating the nth term using:

a(n) = a + (n - 1) * d

This gives

a(n) = 7 + (n - 1) * 9

Evaluate the product

a(n) = 7  - 9 + 9n

Evaluate the difference

a(n) = 9n - 2

So, the sigma notation is:

\sum\limits^7_{n=1} {9n - 2}

Read more about arithmetic series at:

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3 0
3 years ago
A rectangular field is fully enclosed with 218 meters of fencing. The length of the field is
mestny [16]

The length and width of a rectangular field fully enclosed with 218 metes fencing  are 63 meters and 46 meters respectively.

The perimeter of a rectangle is the sum of the whole four sides. Therefore, the perimeter of a rectangle is defined as follows:

  • perimeter = 2(l + w)

where

l = length

w = width

perimeter = 218 meters

The length of the field is  17 meters longer than the width, w. Therefore, the length is defined as follows:

  • l = 17 + w

The length and the width can be calculated as follows:

218 = 2(l + w)

218 = 2(17 + w + w)

218 = 34 + 4w

218 - 34 = 4w

184 = 4w

divide both sides by 4

w = 184 / 4

w = 46 meters

length = 17 + 46

length = 63 meters

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8 0
3 years ago
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