Almost got it!
x + 3 = 3(y + 2)/2 [Multiplied both sides by 3]
so x + 3 = (3y + 6)/2
2(x + 3) = 3y + 6 [Multiplied both sides by 2]
2x + 6 = 3y + 6
2x = 3y [Subtracted 6 from both sides]
x = 3y/2 [Divided both sides by 2]
x/3 = y/2 [Divided both sides by 3]
So you wrote y/3 instead of y/2
Hope this helped!
y-3=3(x+1)
opening the bracket
y-3=3x+3
y=3x+3+3
equation of the line in the form y=mx+c;
y=3x+6
therefore gradient=3
parallel lines have same gradient therefore gradient of the other line is 3
y--3/x-0=3
y+3=3(x-0)
y+3=3x-0
y=3x-3.
Answer:
sqrt(11)
Step-by-step explanation:
3^3+sqrt2^2=11
Answer: The answer to a system of equations is the point(s) of intersection of the equation involved.
When you have more than one equation with more than one variable, you have a system of equation. The solution(s) is the set of values for each variable that satisfy the equations. This means that the inputting values make the equations true.
5 hours and 30 minutes ya que ambos trabajaran la mitad del trabajo
