Answer:
no solution
Step-by-step explanation:
simplifying
6(y + -5) = 2(10 + 3y)
reorder the terms:
6(-5 + y) = 2(10 + 3y)
(-5 * 6 + y * 6) = 2(10 + 3y)
(-30 + 6y) = 2(10 + 3y)
-30 + 6y = (10 * 2 + 3y * 2)
-30 + 6y = (20 + 6y)
add '-6y' to each side of the equation.
-30 + 6y + -6y = 20 + 6y + -6y
combine like terms: 6y + -6y = 0
-30 + 0 = 20 + 6y + -6y
-30 = 20 + 6y + -6y
combine like terms: 6y + -6y = 0
-30 = 20 + 0
-30 = 20
solving for:
-30 = 20
the left and right sides are not equal, so there isn't any solution!
Answer:
11/12
Step-by-step explanation:
We need to get a common denominator of 12
2/3 *4/4 = 8/12
1/4 *3/3 = 3/12
2/3 +1/4
8/12+3/12
11/12
The total distance traveled by the robot from t=0 to t=9 is 1422 units
Integration is a way in which smaller components are brought together in pieces to form a whole. Integration can be used in finding areas, volumes and so on.
Given that the position s(t) at any time t is given by the function:
s(t)=9t²−90t+4
The total distance traveled by the robot from t=0 to t=9 can be gotten by integrating the position function within the limits 0< t < 9
Therefore:
![Total\ distance = \int\limits^9_0 {s(t) \, dt \\\\Total\ distance = \int\limits^9_0 {(9t^2-90t+4) \, dt\\\\Total\ distance = [3t^3-45t+4t]_0^9\\\\Total\ distance=-1422\ units](https://tex.z-dn.net/?f=Total%5C%20distance%20%3D%20%5Cint%5Climits%5E9_0%20%7Bs%28t%29%20%5C%2C%20dt%20%5C%5C%5C%5CTotal%5C%20distance%20%3D%20%5Cint%5Climits%5E9_0%20%7B%289t%5E2-90t%2B4%29%20%5C%2C%20dt%5C%5C%5C%5CTotal%5C%20distance%20%3D%20%5B3t%5E3-45t%2B4t%5D_0%5E9%5C%5C%5C%5CTotal%5C%20distance%3D-1422%5C%20units)
The total distance is 1422 units
Find out more at: brainly.com/question/22008756
I see this as a basic equation.
If she starts at point x, 8 feet, then goes down another 13, she is adding to the number of feet she traveled down.
So your answer would be 8+13=21
If this isn't what you needed, because I am not sure what math you are taking, let me know if I can help you more!
Answer:
907.46 mm2
Step-by-step explanation:
Area of circle = (¶d^2)/4
d = 34 mm
Therefore
Area A = (3.14 x 34^2)/4
= 907.46 mm2
