The volume of a square pyramid can be derived from the expression that the volume of an object is equal to the product of the area of the base times its height. For a square pyramid, it can be simplified as V = a^2(h)/3 where a is the side of the square base and h is the height. However, we are given the slant height. The equation would be:
V = a^2(h)/3
s^2 = (a/2)^2 + h^2 where s is the slant height
h = √( s^2 - (a/2)^2)
h = √( 26^2 - (48/2)^2)= 10
V = 48^2(10)/3 = 7680 cm^3 --> OPTION C
-5x - 3(-x+3x) - 5
1.) -3(-x+3x) = 3 - 9x
2.) -5 + 3x - 9x - 5
3.) 3x - 9x = -6x
4.) -5x - 6x -5
5.) -5x - 6x = -11x
6.) -11x - 5
answer is : -11x-5
Answer:
Step-by-step explanation:
All are relations except for relation 3
