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Arada [10]
2 years ago
14

Write the equation of a line in slope-intercept form that goes through the points

Mathematics
1 answer:
Stella [2.4K]2 years ago
5 0

Answer: The equation in slope-intercept form is y=2x-11

Step-by-step explanation: Slope-intercept is y=mx+b where m is the slope and b is the y-intercept. To find the slope, you find the difference between the y values divided by the difference between the x values. -5-(-9) = 4, and 3-1 is 2. 4/2 is 2, so m = 2. Since the slope is 2, it states for every x you move on the right you move 2 up. But we are trying to get the y-intercept, so x = 0. We are subtracting 1 in our x value, so we move 2 downwards. We subtract 2 from -9 which gives us -11, which is our y-intercept.

Hope this helps!

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What is 11x(-6)?<br> please answer i really need this!
navik [9.2K]

Answer:

-66

Step-by-step explanation:

11 × (-6) = -66

8 0
3 years ago
Read 2 more answers
The distribution of the amount of money in savings accounts for Florida State students has an average of 1,200 dollars and a sta
Anestetic [448]

Answer:

By the Central Limit Theorem, the sampling distribution of the sample mean amount of money in a savings account is approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Average of 1,200 dollars and a standard deviation of 900 dollars.

This means that \mu = 1200, \sigma = 900

Sample of 10.

This means that n = 10, s = \frac{900}{\sqrt{10}} = 284.6

The sampling distribution of the sample mean amount of money in a savings account is

By the Central Limit Theorem, approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.

7 0
3 years ago
The number of orders received daily by an online vendor of used CDs is normally distributed with mean 270 and standard deviation
frez [133]

Answer:

Step-by-step explanation:

Given that the number of orders received daily by an online vendor of used CDs (say X) is normally distributed with mean 270 and standard deviation 16.

X is N(270, 16)

To find percentage of days will the company have to hire extra help or pay​ overtime, we can find probability using std normal table

X>302 means

Z>\frac{302-270}{16} =2

P(Z>2) = 0.25

Thus 25% of days will the company have to hire extra help or pay​ overtime

4 0
3 years ago
SIMPLIFY THE EXPRESSION: 2(4+5v)<br><br>PLS HELPPPPP ILL GIVE U BRAINLIEST
Lyrx [107]

Answer:

8+10v

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A man flies a kite at a height of 16 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. How fast
Talja [164]

Answer:

4.41 feet per second.

Step-by-step explanation:

Please find the attachment.

We have been given that a man flies a kite at a height of 16 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. We are asked to find how fast must he let out the string when the kite is flying on 34 ft. of string.

We will use Pythagoras theorem to solve for the length of side x as:

x^2+16^2=34^2

x^2=34^2-16^2

x^2=900\\\\x=30

Now, we will use Pythagorean theorem to relate x and y because we know that the vertical side (16) is always constant.

x^2+16^2=y^2

Let us find derivative of our equation with respect to time (t) using power rule and chain rule as:

2x\cdot \frac{dx}{dt}+0=2y\cdot \frac{dy}{dt}

We have been given that \frac{dx}{dt}=5 , y=34 and x=30.

2(30)\cdot 5=2(34)\cdot \frac{dy}{dt}

300=68\cdot \frac{dy}{dt}

\frac{dy}{dt}=\frac{300}{68}

\frac{dy}{dt}=4.4117647058823529

\frac{dy}{dt}\approx 4.41

Therefore, the man must let out the string at a rate of 4.41 feet per second.

8 0
3 years ago
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