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Sedbober [7]
3 years ago
11

The number of orders received daily by an online vendor of used CDs is normally distributed with mean 270 and standard deviation

16. The company has to hire extra help or pay overtime on those days when the number of orders received is 302 or higher. What percentage of days will the company have to hire extra help or pay​ overtime?
Mathematics
1 answer:
frez [133]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that the number of orders received daily by an online vendor of used CDs (say X) is normally distributed with mean 270 and standard deviation 16.

X is N(270, 16)

To find percentage of days will the company have to hire extra help or pay​ overtime, we can find probability using std normal table

X>302 means

Z>\frac{302-270}{16} =2

P(Z>2) = 0.25

Thus 25% of days will the company have to hire extra help or pay​ overtime

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Building a has 7,500 ft of an office space for 320 employees building b has 9,500 square feet of office space for 370 employees
iren2701 [21]

Answer:

I believe the correct answer is Building B

Step-by-step explanation:

Building A is 23.45 per employee and Building B is 25.67 per employee

4 0
3 years ago
Can you please help me with this one please
son4ous [18]
The volume of this box is indeed 84 in^3.  What were you looking for beyond that?

Base:  (7 in)(3 in) = 21 in^2
Height:  4 in
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5 0
4 years ago
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What is the domain of the function? y=3√x-1
geniusboy [140]
X - 1 is inside a cubic root.
The cubic root of a positive number is positive.
The cubic root of zero is zero.
The cubic root of a negative number is negative.
That means that the cubic root of any real number is also a real number.
The domain is all real numbers.
Answer: Choice A.
3 0
3 years ago
f) The life of a power transmission tower is exponentially distributed, with mean life 25 years. If three towers, operated indep
Step2247 [10]

Answer:

15.24% probability that at least 2 will still stand after 35 years

Step-by-step explanation:

To solve this question, we need to understand the binomial distribution and the exponential distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Probability of a single tower being standing after 35 years:

Single tower, so exponential.

Mean of 25 years, so m = 25, \mu = \frac{1}{25} = 0.04

We have to find P(X > 35)

P(X > 35) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-0.04*35} = 0.2466

What is the probability that at least 2 will still stand after 35 years?

Now binomial.

Each tower has a 0.2466 probability of being standing after 35 years, so p = 0.2466

3 towers, so n = 3

We have to find:

P(X \geq 2) = P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.2466)^{2}.(0.7534)^{1} = 0.1374

P(X = 3) = C_{3,3}.(0.2466)^{3}.(0.7534)^{0} = 0.0150

P(X \geq 2) = P(X = 2) + P(X = 3) = 0.1374 + 0.0150 = 0.1524

15.24% probability that at least 2 will still stand after 35 years

4 0
3 years ago
If ∠D is a supplementary angle of ∠E and ∠F is a supplementary angle of ∠E, then which of the following statements is true?
Romashka [77]

Answer:

A) ∠D ≅ ∠F

Step-by-step explanation:

<u>Supplementary angles</u> : A pair of angles whose sum is 180° are called supplementary angles

We are given that ∠D is a supplementary angle of ∠E

So,\angle D+\angle E = 180^{\circ} -----1

We are also given that ∠F is a supplementary angle of ∠E

So,\angle F+\angle E = 180^{\circ} ------2

Find the value of ∠E form 1 and 2

From 1 : \angle E = 180^{\circ}-\angle D

From 2 : \angle E = 180^{\circ}-\angle F

So, 180^{\circ}-\angle D=180^{\circ}-\angle F

\angle D=\angle F

So, Option A is true

Hence ∠D ≅ ∠F

3 0
3 years ago
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