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3 years ago

Find the volume of the prism.

Mathematics

1 answer:

puteri [66]3 years ago

7 0

Answer:

Volume of prism = 6.3 cm³

Step-by-step explanation:

Given:

Dimensions of parallels line = 2.3 and 1.2 cm

Height of prism = 1.8 cm

Width of prism = 2 cm

Find:

Volume of prism

Computation:

Volume of prism = Area of base x Width

Volume of prism = [(1/2)(sum of parallels line)(Height)]Width

Volume of prism = [(1/2)(2.3 + 1.2)(1.8)]2

Volume of prism = [(1/2)(3.5)(1.8)]2

Volume of prism = [(3.5)(1.8)]

Volume of prism = 6.3 cm³

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For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

Ali’s dog weighs 8 times as much as her cat. Together, the two pets weigh 54 pounds. How much does Ali’s dog weigh?

baherus [9]

Ali's dog weighs 48 pounds.

5 0

3 years ago

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Plz help me I really need it

IrinaVladis [17]

Answer:

i think [after solving] that it is option B and C

Step-by-step explanation:

4 0

3 years ago

I dont know how to do math 10 factors

pav-90 [236]

Answer:

10= 1 , 2 , 5 and 10

Step-by-step explanation:

Those are the factors of 10

4 0

3 years ago

Question 1 of 40<br> If f(x) = 4x² - 6 and g(x) = x² - 4x-8, find (f- g)(x).

Aleksandr-060686 [28]

Answer:

$\huge\boxed{\sf (f-g)(x) = 3x\² + 4x - 14}$

Step-by-step explanation:

<h3><u>Given functions:</u></h3>

f(x) = 4x² - 6
g(x) = x² - 4x - 8

<h3><u>Solution:</u></h3>

Subtract both functions

(f-g)(x) = 4x² - 6 - (x² - 4x - 8)

(f-g)(x) = 4x² - 6 - x² + 4x - 8

Combine like terms

(f-g)(x) = 4x² - x² + 4x - 6 - 8

(f-g)(x) = 3x² + 4x - 14

$\rule[225]{225}{2}$

3 0

2 years ago

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