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sladkih [1.3K]
3 years ago
10

(right person gets 44 points!!)

Mathematics
2 answers:
Sergio [31]3 years ago
8 0

Answer:

I'm not 10)% sure but I believe it's A.

Step-by-step explanation:

Makovka662 [10]3 years ago
8 0

Answer:

Answer C (Atleast 140 guests)

Step-by-step explanation:

First you have to add $2+0.50=$2.5 you have to divide $350 by $2.5 to get 140 guests

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What is the decrease of a right angle pls help i suck at math NVM ITS 90
Nookie1986 [14]

Answer: 90 degrees

Step-by-step explanation:

7 0
3 years ago
your planning to build a boat. you have a sample board of wood that you want to use . the board has an area of 1/3 ft squared an
frosja888 [35]
Given:
Area of sample board: 1/3 square ft.
Weight of sample board: 1/5 lbs

We need to get the weight of the whole square foot.

1/3 square foot is only a part of the whole square foot. Its corresponding weight is 1/5 pounds. We need to divide the area by its corresponding weight to get the total weight per square foot.

1/3 ÷ 1/5 

Rules of dividing fractions:
1st fraction: 1/3 ; 2nd fraction: 1/5

1) Get the reciprocal of the 2nd fraction. 1/5 ⇒ 5/1

2) Multiply 1st fraction to the reciprocal of the 2nd fraction
1/3 * 5/1 = 5/3

3) Simplify fraction.
5/3 is an improper fraction. To simplify it, it needs to become a mixed fraction.

5/3 = 1 2/3 pounds.



8 0
4 years ago
|60| ___ |-60|<br><br> which one fits to make it correct?<br><br> &gt; <br> =
Alika [10]
=

absolute values are always positive.
6 0
3 years ago
Read 2 more answers
Your body loses sodium when you sweat. Researchers sampled 38 random tennis players. The average sodium loss was 500 milligrams
Salsk061 [2.6K]

Answer:

The 99% confidence interval to estimate the mean loss in sodium in the population is between 474.10 milligrams and 525.90 milligrams. This means that we are 99% that the true mean loss in sodium in the population is between 474.10 milligrams and 525.90 milligrams.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575*\frac{62}{\sqrt{38}} = 25.90

The lower end of the interval is the mean subtracted by M. So it is 500 - 25.90 = 474.10 milligrams.

The upper end of the interval is the mean added to M. So it is 500 + 25.90 = 525.90 milligrams

The 99% confidence interval to estimate the mean loss in sodium in the population is between 474.10 milligrams and 525.90 milligrams. This means that we are 99% that the true mean loss in sodium in the population is between 474.10 milligrams and 525.90 milligrams.

7 0
3 years ago
The annual rainfall (in inches) in a certain region is normally distributed with µ = 40 and σ = 4. What is the probability that
Allushta [10]

Answer:

P( That it will take over 10 years or more of a year with a rainfall above 50inches) = (0.9938)^10

Step-by-step explanation:

Since the annual rainfall is normally distributed,

Given: that

Mean (µ )= 40

and σ = 4.

Let X be normal random variables of the annual rainfall.

P(that there will be over 10 years or more before a year with a rainfall above 50 inches)

P(>50) = 1-P[X ≤50]

1 - P[X- μ/σ ≤ 50 - 40/4]

=1 - P [Z≤ 5/2]

=1 -Φ(5/2)

=1 - 0.9939

= 0.0062

P( the non occurrence of rainfall above 50 inches)

= 1-0.0062

=0.9938

ASSUMPTION:

P( That it will take over 10 years or more of a year with a rainfall above 50inches) =(0.9938)^10

4 0
3 years ago
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