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Arada [10]
2 years ago
6

The polynomial P(z) =

^{3} +mz^{2} +nz - 8" alt="z^{3} +mz^{2} +nz - 8" align="absmiddle" class="latex-formula"> is divisible by (z+1+i), where z ∈C, m,n ∈R. Find the value of m and of n.
Mathematics
1 answer:
Ugo [173]2 years ago
3 0

Answer:

m=-2   n=-6

Step-by-step explanation:

(z+1+i)(z+1-i)=z²+2z+1-(i²)=z²+2z+2

z³+mz²+nz-8=(z²+2z+2)(z-4)=z³-2z²-6z-8

m=-2

n=-6

If it's wrong, please delete it

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13C_5=\frac{(13 \times12 \times11 \times10 \times9 \times8\times7 \times6 \times5 \times4 \times3 \times2 \times1)}{(8 \times7 \times6 \times5 \times4 \times3 \times2 \times1)(5 \times4 \times3 \times2 \times1)}

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