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DiKsa [7]
3 years ago
5

X3 + 2xsquared - x - 2 = (x + 6_)(x + 2_)(x + 4_)

Mathematics
1 answer:
Anon25 [30]3 years ago
3 0
3345 because it’s squared
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3x - 3y = 9 and x + 3y = 12 <br> Elimination
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Answer:

x=5.25,y=2.25

Step-by-step explanation:

We can add the two equations to eliminate the variable y and solve for x:

3x-3y+x+3y=9+12

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Now, we can use substitution to solve for y:

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<h2> S.O.L.V.E</h2>

  1. Study the problem
  2. Organize your facts
  3. Line up the problem
  4. Validate
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<h2 />

<h2><em>step</em><em> </em><em>1</em><em> </em><em>:</em><em>study</em><em> </em><em>the</em><em> </em><em>problem</em><em> </em></h2>

<em>write</em><em> </em><em>down</em><em> </em><em>your</em><em> </em><em>fact</em><em> </em><em>or</em><em> </em><em>what</em><em> </em><em>you</em><em> </em><em>know</em><em> </em><em>about</em><em> </em><em>the</em><em> </em><em>problem</em><em>. </em><em>also</em><em> </em><em>crossout</em><em> </em><em>unnecessary</em><em> </em><em>parts</em><em> </em><em>of</em><em> </em><em>the problem</em><em> </em><em>and</em><em> </em><em>highlight</em><em> </em><em>important</em><em> </em><em>information</em><em>.</em>

example: X = hours

<h2> </h2><h2>Step 2: organize your facts</h2>

organize your facts means put in order ,write what it means etc.

example: the problem say rebbeca has 3 3 times as much candy than Sara. what does the problem mean ?

<h2>Step 3 : line up your strategy. </h2><h3> what are your plans for solving this problem ? what operation will u do ? how much step is in this problem ? does this make sense ? in line up your strategy u have to think about why I'm doing this? how I will do this etc.</h3>

<h2>Step 4 : validate </h2>

<h3>"SOLVE THE PROBLEM"!</h3>

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\bf h=-15cos\left( \frac{2\pi }{5}t \right)\qquad \boxed{h=8}\qquad 8=-15cos\left( \frac{2\pi }{5}t \right)&#10;\\\\\\&#10;\cfrac{8}{-15}=cos\left( \frac{2\pi }{5}t \right)\implies cos^{-1}\left(  \frac{8}{-15}\right)=cos^{-1}\left[ cos\left( \frac{2\pi }{5}t \right) \right]&#10;\\\\\\&#10;cos^{-1}\left(  \frac{8}{-15}\right)=\cfrac{2\pi }{5}t\implies \cfrac{5}{2\pi }\cdot  cos^{-1}\left(  \frac{8}{-15}\right)=t\\\\&#10;-------------------------------

\bf cos^{-1}\left(  \frac{8}{-15}\right)=\stackrel{radians}{\stackrel{II~quadrant}{\approx 2.13}~~,~~\stackrel{III~quadrant}{\approx 4.15}}\qquad \qquad &#10;t=&#10;\begin{cases}&#10;\frac{5}{2\pi }\cdot 2.13\\\\&#10;\frac{5}{2\pi }\cdot 4.15&#10;\end{cases}
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