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olya-2409 [2.1K]
3 years ago
9

EXPERTS PLEASE HELP!!!!!!!!!!!!!!

Mathematics
1 answer:
Arturiano [62]3 years ago
7 0

Answer:

1. D

2. x=65

Step-by-step explanation:

Hi!

Your answer is D because 78 is 120% of x

120% in decimal point is 1.2.

So it's 1.2x is the same as 120% of x

For question 8:

1.2x=78

Isolate x by divide 1.2 on both sides

78/1.2=65

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I really need an answer as soon as possible. 10 pts worth it
viva [34]

Answer:

A. Correct: When we plug in g(x) for the x in f(x), we get H(x).

B. Correct: When we plug in g(x) for the x in f(x), we get H(x).

C. Correct: When we plug in g(x) for the x in f(x), we get H(x).

D. Correct: When we plug in g(x) for the x in f(x), we get H(x).

Step-by-step explanation:

<em>Brainliest, please!</em>

8 0
3 years ago
Hellp pls. This is not a test, so pls do not report.
SashulF [63]
B is the correct answer

7 0
2 years ago
Item 25
Julli [10]

Answer:

135,910

Step-by-step explanation:

Add all  assets together and you will get this answer.

8 0
3 years ago
Plz help<br>urgent !!!!<br>will give the brainliest !!​
Mkey [24]

Answer:

X = \begin{bmatrix}1&3\\ 2&4\end{bmatrix}

Step-by-step explanation:

The question we have at hand is, in other words,

\begin{bmatrix}4&2\\ \:1&1\end{bmatrix}\left(X\right)=\begin{bmatrix}8&20\\ \:3&7\end{bmatrix} - where we have to solve for the value of X

If we have to isolate X here, then we would have to take the inverse of the following matrix ...

\begin{bmatrix}4&2\\ \:1&1\end{bmatrix} ... so that it should be as follows ... \begin{bmatrix}4&2\\ \:1&1\end{bmatrix}^{-1}

Therefore, we can conclude that the equation as to solve for " X " will be the following,

X=\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1}\begin{bmatrix}8&20\\ 3&7\end{bmatrix} - First find the 2 x 2 matrix inverse of the first portion,

\begin{bmatrix}4&2\\ 1&1\end{bmatrix}^{-1} = \frac{1}{\det \begin{pmatrix}4&2\\ 1&1\end{pmatrix}}\begin{pmatrix}1&-2\\ -1&4\end{pmatrix}= \frac{1}{2}\begin{bmatrix}1&-2\\ -1&4\end{bmatrix} = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}

At this point we have to multiply the rows of the first matrix by the rows of the second matrix,

X = \begin{bmatrix}\frac{1}{2}&-1\\ -\frac{1}{2}&2\end{bmatrix}\begin{bmatrix}8&20\\ 3&7\end{bmatrix} ,

X = \begin{pmatrix}\frac{1}{2}\cdot \:8+\left(-1\right)\cdot \:3&\frac{1}{2}\cdot \:20+\left(-1\right)\cdot \:7\\ \left(-\frac{1}{2}\right)\cdot \:8+2\cdot \:3&\left(-\frac{1}{2}\right)\cdot \:20+2\cdot \:7\end{pmatrix} - Simplifying this, we should get ...

\begin{bmatrix}1&3\\ 2&4\end{bmatrix} ... which is our solution.

7 0
3 years ago
Location of bern as an ordered pair please help
navik [9.2K]

Answer:

Step-by-step explanation:

(3,-3)

4 0
3 years ago
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