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3 years ago

Which set is closed under subtraction?

Mathematics

2 answers:

AURORKA [14]3 years ago

8 0

The set that is closed under subtraction is rational numbers

Marrrta [24]3 years ago

5 0

Answer:

The correct answer is rational numbers.

Step-by-step explanation:

We consider that a set is closed when the two elements that are part of an operation result in an element belonging to the same group.

As for rational numbers, they are all those that can be represented as the quotient of two whole numbers or, a whole and a positive natural.

These types of numbers are considered in a set closed under addition, subtraction, and multiplication.

Given this information we can say that the correct answer is rational numbers.

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Which function represents the cost of a pizza with n Toppings

alukav5142 [94]

Correct answer is B... You can plug in values for n. Plug in 1 for n and the out put is 12. Plug in 2 for n and the output is 13.5

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3 years ago

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Erin buys a bag of peanuts that weighs 3/4 of a pound.later that week the bag is 2/3 full how much does the back of peanuts weig

nasty-shy [4]

The answer is 1/2lbs, here's how.

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3 years ago

The velocity,v of a missile is related to time t, By the equation v=5t^2+3t+1.calculate the time at which the velocity is minimu

Cloud [144]

Answer:

time: t = -0.3
minimum: v = 0.55

Step-by-step explanation:

For quadratic ax^2 + bx + c, the extreme value is found at x=-b/(2a). For your quadratic, the minimum is found at ...

t = -(3)/(2(5))

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The value of velocity at that time is ...

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v = 0.55 . . . . . value of minimum velocity

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3 years ago

Quadrilateral RSTU has vertices R(1,3), S(4,1), T(1,-3) and U(-2,-1). Is it true or false that this is a rectangle because the d

Alex777 [14]

Given vertices ofQuadrilateral RSTU as R(1,3), S(4,1), T(1,-3) and U(-2,-1).

We need to check if diagonals are congruent.

The coordinates of verticales diagonal RT are R(1,3) and T(1,-3).

The coordinates of verticales diagonal SU are S(4,1), and U(-2,-1),

By applying distance formula:

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

RT = $=\sqrt{\left(1-1\right)^2+\left(-3-3\right)^2}$ = $\sqrt{36}$

RT = 6

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$=2\sqrt{10}$ .

Diagonal RT is not congruent to Diagonal SU.

Therefore, Quadrilateral RSTU is not a rectangle because the diagonals are not congruent.

So, it is False.

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3 years ago

Question 2 of 5 ✓25 = O A. 10 B. 6 C. 4 D. 5

Elenna [48]

Answer:

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