Critical values are values where f'(x)=0 and the bounds of a function. Thus, let's solve for f'(x)!
f(x)=2x^3-3x^2+3x+8
f'(x)=6x^2-6x+3
Now let's set f'(x)=0
0=6x^2-6x+3
0=2x^2-2x+1
As it turns out, 2x^2-2x+1 isn't factorable!
This saves me some time because this means there are no critical numbers!
Answer:
No it is not satisfied
Step-by-step explanation:
The one-way ANOVA is used to measure whether the difference between the means of two independent groups are statistically significant.
For it to be satisfied, there has to be one independent variable which is categorical and one dependent variable. The dependent variable on its own has to be a continuous variable
The assumptions are:
1. Equal variance between population
2. Independence between observations
3. The random samples have to be gotten from a normal population.
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Answer:
see attached
Step-by-step explanation:
You want a line that goes through (0, 0) and has a slope of 5. That means it will also go through (1, 5) and (2, 10), for example. I like the attached graphing tool because it will draw the graph directly from the equation.
