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3 years ago

6

Hello!! I have a question, can you please answer it. ^^

1 answer:

xeze [42]3 years ago

5 0

Answer:

1. 75

2. 1

Step-by-step explanation:

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A meter stick casts a shadow 2.4 m long at the same time a flagpole casts a shadow 9.7 m long. How tall is the flagpole

Luda [366]

The first thing we are going to do is draw a diagram of the situation to help us to solve the situation.
We an draw tow similar triangle between the length of the shadows and the height of the stick and the pole.
Since <span>meter stick has a length of 1 meter, the height of our smaller triangle is 1 meter. Let </span> $h$ be height of of the pole. Since both triangles are similiar we can establish a proportion between their corresponding sides and solve for $h$ :
$\frac{h}{1} = \frac{9.7}{2.4}$
$h=\frac{9.7}{2.4}$
$h=4.04$

We can conclude that the pole is 4.04 meters tall.

8 0

2 years ago

Given f(x)=14(5−x)2 what is the value of f(11)?

dlinn [17]

Answer:

I was unsure about the way your question was written so I solved for two equations: f(x)=14(5-x)*2 and f(x)=14(5-x)+2

Step-by-step explanation:

8 0

2 years ago

An enclosed gas exerts a pressure P on the walls of a container. This pressure is directly proportional to the temperature T of

tatyana61 [14]

Don't know if i'm right but I got 1/60

5 0

2 years ago

Read 2 more answers

A radioactive substance decays exponentially: The mass at time t is m(t) = m(0)ekt, where m(0) is the initial mass and k is a ne

velikii [3]

Answer:

M = 1/0.000121 = 8264.5 years

Step-by-step explanation:

M = − k ∫∞₀ teᵏᵗdt

To obtain this mean life, we'll use integration by parts to integrate the function ∫ teᵏᵗdt

∫udv = uv - ∫ vdu

u = t

du/dt = 1

du = dt

∫ dv = ∫ eᵏᵗdt

v = eᵏᵗ/k

∫udv = ∫ teᵏᵗdt

uv = teᵏᵗ/k

∫ vdu = eᵏᵗ/k

∫ teᵏᵗdt = (teᵏᵗ/k) - ∫eᵏᵗ/k

But, ∫eᵏᵗ/k = (1/k) ∫eᵏᵗ = (1/k²) eᵏᵗ = eᵏᵗ/k²

∫ teᵏᵗdt = (teᵏᵗ/k) - eᵏᵗ/k²

The rest of the calculation is done on paper in the image attached to this question

3 0

2 years ago

We can measure temperature in two different common units degrees Celsius in degrees Fahrenheit the variable X represents the tem

labwork [276]

Answer: 50° Fahrenheit

Step-by-step explanation:

Here, the equation that shows the temperature of x degree Celsius in Fahrenheit is,

$F(x) = 32^{\circ} + 1.8\times x$

Where x is a variable.

Thus, For the temperature of 10° Celsius,

x = 10° Celsius

The temperature in Fahrenheit is,

$F(10^{\circ}C) = 32^{\circ} + 1.8\times 10$

$= 32^{\circ} + 18^{\circ}$

$=50^{\circ}\text{ Fahrenheit}$

Thus, the increasing temperature by 10° C is equivalent to increasing temperature by 50° F.

5 0

3 years ago