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3 years ago

I WILL GIVE BRAINLIEST ONLY IF YOU ANSWER WELL

Mathematics

2 answers:

Ivan3 years ago

5 0

Answer:

I dont know im in middle school can you please giva me one i have to get my grades up

Step-by-step explanation:

Maurinko [17]3 years ago

3 0

Answer:

Step-by-step explanation:

(1)

(25)

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Find the area of the figure. Use 3.14 as π.

Karolina [17]

Answer: D. 94.25 in²

Step-by-step explanation:

To find the total area, we will break the shape up into two different parts.

[] The rounded part is 39.25 in². Let us assume the rounded part is exactly half of a circle.

Area of a circle:

A = πr²

Use 3.14 for pi:

A = (3.14)r²

Find the radius:

d / 2 = r, 10 / 2 = 5 in

Subsittue:

A = (3.14)(5)²

A = 78.5 in²

Divide by 2 since it is only half:

78.5 in² / 2 = 39.25 in²

[] The triangle is 55 in².

Area of a triangle:

A = b*h/2

A = 11 * 10 / 2

A = 110 / 2

A = 55 in²

[] Total area. We will add the two parts together.

55 in² + 39.25 in² = 94.25 in²

7 0

2 years ago

Read 2 more answers

Joy is helping her father to build a rectangular deck that measures 14 ft by 19 ft.

Helga [31]

14 multiplied by 9 is 126
The answer is 126ft

7 0

3 years ago

What is the slope of line PQ?

Anit [1.1K]

Answer:

Step-by-step explanation:

Slope of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula,

Slope = $\frac{y_2-y_1}{x_2-x_1}$

Slope of the line PQ passing through the two points P(-8, 2) and Q(4, 2) will be,

Slope ' $m_1$ ' = $\frac{2-2}{-8-2}$ = 0

Therefore, slope of the line PQ parallel to the x-axis = 0

Slope of the line MN passing through the points M(8, 6) and N(8, -8) is,

Slope ' $m_2$ ' = $\frac{6+8}{8-8}$ = ∞

Therefore, slope of the line MN parallel to y-axis is undefined.

Since, angle between the x-axis and y-axis is 90°,angle at the intersection point between the lines parallel to x and y axis will be 90°.

These lines are perpendicular to each other.

4 0

4 years ago

aleksley [76]

Answer:

a=1.66

b=8368.12

Step-by-step explanation:

hope it helps

8 0

2 years ago

An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individ

Tema [17]

Answer:

a) P=0.558

b) P=0.021

Step-by-step explanation:

We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.

The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

$P(x=k)=\frac{\lambda^ke^{-\lambda}}{k!} =\frac{4^ke^{-4}}{k!}$

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:

$P(4\leq x\leq 9)=\sum_{k=4}^9P(k)\\\\\\ P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\P(9)=4^{9} \cdot e^{-4}/9!=262144*0.0183/362880=0.013\\\\\\$

$P(4\leq x\leq 9)=\sum_{k=4}^9P(k)=0.195+0.156+0.104+0.060+0.030+0.013=0.558$

b) The approximate probability that at least 9 carry the gene is:

$P(x\geq9)=1-P(x\leq 8)\\\\\\$

$P(0)=4^{0} \cdot e^{-4}/0!=1*0.0183/1=0.018\\\\P(1)=4^{1} \cdot e^{-4}/1!=4*0.0183/1=0.073\\\\P(2)=4^{2} \cdot e^{-4}/2!=16*0.0183/2=0.147\\\\P(3)=4^{3} \cdot e^{-4}/3!=64*0.0183/6=0.195\\\\P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\$

$P(x\geq9)=1-P(x\leq 8)\\\\P(x\geq9)=1-(0.018+0.073+0.147+0.195+0.195+0.156+0.104+0.060+0.030)\\\\P(x\geq9)=1-0.979=0.021$

8 0

3 years ago