If the radius is 13 what is the circumference?

Mathematics

1 answer:

shepuryov [24]2 years ago

8 0

Answer:81.64

Step-by-step explanation:13x2=26 26x3.14=81.64

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cos theta = 4/5, 0˚< theta < 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta

NikAS [45]

First calculate $\sin\theta$ .

$\sin^2\theta+\cos^2\theta=1\\\\\sin^2\theta=1-\cos^2\theta\\\\\sin^2\theta=1-\left(\dfrac{4}{5}\right)^2\\\\\\\sin^2\theta=1-\dfrac{16}{25}\\\\\\\sin^2\theta=\dfrac{9}{25}\quad|\sqrt{(\dots)}\\\\\\\sin\theta=\sqrt{\dfrac{9}{25}}\\\\\\\boxed{\sin\theta=\dfrac{3}{5}}$

We take positive value of sinθ because 0° < θ < 90°
Now we could calculate sin2θ, cos2θ and tan2θ:

$\sin2\theta=2\sin\theta\cos\theta=2\cdot\dfrac{3}{5}\cdot\dfrac{4}{5}=\dfrac{2\cdot3\cdot4}{5\cdot5}=\dfrac{24}{25}\\\\\\\cos2\theta=\cos^2\theta-\sin^2\theta=\left(\dfrac{4}{5}\right)^2-\left(\dfrac{3}{5}\right)^2=\dfrac{16}{25}-\dfrac{9}{25}=\dfrac{7}{25}\\\\\\
\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=\dfrac{\frac{24}{25}}{\frac{7}{25}}=\dfrac{24\cdot25}{7\cdot25}=\dfrac{24}{7}=3\dfrac{3}{7}$

5 0

2 years ago

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-3(6v-4)+6v=-2(v+3) HOW CAN I SIMPLIFY THIS

ddd [48]

Subtract 12 from each side
so it should look like this
-12v=-2v-18
now add 2v to each side
so it should look like this
-10v=-18
now divdie each side by -10
and you should get
v=9/5 or 1 4/5

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3 years ago

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What is the last term of 0.03,0.06,0.12,,,,,,1.92

hjlf

There is no "last term." Since the pattern is increasing by .03 each time, then the pattern continues forever.

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3 years ago

Using the image below, determine the measure of angle RTQ.

11111nata11111 [884]

Answer:

$m\angle RTQ = 63^\circ$