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Verdich [7]
3 years ago
14

Least common multiple for (x+3)^2(x-2) and (x+3)(x^2-16)

Mathematics
1 answer:
Gennadij [26K]3 years ago
8 0

{(x + 3)}^{2}(x - 2)(x + 4)(x - 4)

Step-by-step explanation:

{(x + 3)}^{2} (x - 2)  \:  \:  \: (x + 3)( {x}^{2} - 16)

The first one can be kept in that form while the second can be factored as

(x + 3)(x + 4)(x - 4)

so we can see that the LCM is

{(x + 3)}^{2}(x - 2)(x + 4)(x - 4)

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Chris has some quarters and dimes. He has 14 coins worth a total of $2.60. How many of each type
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Equations:
q + d = 14
0.25q + 0.10d = 2.60

-0.10( q + d = 14 )
0.25q + 0.10d = 2.60

-0.10q - 0.10d = -1.4
0.25q + 0.10d = 2.60
Add up the two equations
0.15q = 1.20
/0.15 on both sides
q = 8

q + d = 14
8 + d = 14
-8 on both sides
d = 6

0.25q + 0.10d = 2.60
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Answer:
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6 Dimes
8 0
4 years ago
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