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Pie
3 years ago
11

What is twice 2 to the 30th power using exponents.

Mathematics
2 answers:
zalisa [80]3 years ago
7 0
4875607 is going to be your answer
dimulka [17.4K]3 years ago
4 0
<span>2^30 is simple for a scientific calculator to do, it is 1,073,741,824,</span>
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Help me please i'm confused again
11Alexandr11 [23.1K]

Answer: 6¹⁰

Step-by-step explanation:

\displaystyle\\6^4*6^6=\\\\6^{4+6}=\\\\6^{10}

6 0
1 year ago
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sveticcg [70]

Answer:

A

Step-by-step explanation:

5 0
1 year ago
The most common form of color blindness is an inability to distinguish red from green. However, this particular form of color bl
Alecsey [184]

Answer:

(a) The correct answer is P (CBM) = 0.79.

(b) The probability of selecting an American female who is not red-green color-blind is 0.996.

(c) The probability that neither are red-green color-blind is 0.9263.

(d) The probability that at least one of them is red-green color-blind is 0.0737.

Step-by-step explanation:

The variables CBM and CBW are denoted as the events that an American man or an American woman is colorblind, respectively.

It is provided that 79% of men and 0.4% of women are colorblind, i.e.

P (CBM) = 0.79

P (CBW) = 0.004

(a)

The probability of selecting an American male who is red-green color-blind is, 0.79.

Thus, the correct answer is P (CBM) = 0.79.

(b)

The probability of the complement of an event is the probability of that event not happening.

Then,

P(not CBW) = 1 - P(CBW)

                   = 1 - 0.004

                   = 0.996.

Thus, the probability of selecting an American female who is not red-green color-blind is 0.996.

(c)

The probability the woman is not colorblind is 0.996.

The probability that the man is  not color- blind is,

P(not CBM) = 1 - P(CBM)

                   = 1 - 0.004  

                   = 0.93.

The man and woman are selected independently.

Compute the probability that neither are red-green color-blind as follows:

P(\text{Neither is Colorblind}) = P(\text{not CBM}) \times  P(\text{not CBW})\\ = 0.93 \times  0.996 \\= 0.92628\\\approx 0.9263

Thus, the probability that neither are red-green color-blind is 0.9263.

(d)

It is provided that a one man and one woman are selected at random.

The event that “At least one is colorblind” is the complement of part (d) that “Neither is  Colorblind.”

Compute the probability that at least one of them is red-green color-blind as follows:

P (\text{At least one is Colorblind}) = 1 - P (\text{Neither is Colorblind})\\ = 1 - 0.9263 \\= 0.0737

Thus, the probability that at least one of them is red-green color-blind is 0.0737.

6 0
3 years ago
Given a sample size of 20, what are the critical values χ2L and χ2R for a 95% confidence level? A. 6.844, 38.582 B. 9.591, 34.17
Novosadov [1.4K]

Answer:

B,C,D

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The college athletic director recorded the highest noise levels reached during 7 sporting events. The highs were:
sergiy2304 [10]

Answer:

90

Step-by-step explanation:

Mean:

(88 + 88 + 88 + 87 + 84 + 97 + 95)/7

627/7

89.57

90

8 0
3 years ago
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