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Arada [10]
3 years ago
5

Please help me solve? (m3n + 8)(m3n - 5) multiplying polynomial by polynomial

Mathematics
1 answer:
ruslelena [56]3 years ago
8 0

The final result should be m^{6}n^{2}  - 3m^{3}n - 40.

In order to multiply any polynomials, use the pattern FOIL (which stands for first, outer, inner, last). You multiply what they ask you to at each step.

First - The first terms in both parenthesis.

m^{3}n * m^{3}n = m^{6}n^{2}

Outer - The terms on the outside of both parenthesis.

m^{3}n * -5 = -5m^{3}n

Inner - The terms on the inside of both parenthesis.

m^{3}n * 8 = 8m^{3}n

Last - the last numbers in each parenthesis.

8 * - 5 = - 40

Now we put all the answers together and simplify like terms,

m^{6}n^{2} + -5m^{3}n + 8m^{3}n - 40

m^{6}n^{2} - 3m^{3}n - 40

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Only the a) part please!!!!
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\implies \begin{pmatrix}6x+y & 2+0 & 10-4\\0+1 & 4x-3y & -6+2\end{pmatrix} =  \begin{pmatrix}31 & 2 & 6\\1 & 17& -4 \end{pmatrix}\\\\\\\implies \begin{pmatrix}6x+y & 2 & 6\\1 & 4x-3y & -4\end{pmatrix} =  \begin{pmatrix}31 & 2 & 6\\1 & 17& -4 \end{pmatrix}\\\\\text{System of equations},\\\\6x +y =31,~~ 4x -3y = 17\\\\\\(iii)\\\\6x +y-31 =0 \\\\4x-3y -17=0\\\\\text{Solving by cross multiplication method}\\\\\\\dfrac x{1(-17) - (-31)(-3)} = \dfrac y{4(-31) - 6(-17)} = \dfrac 1{6(-3) - 4(1)}

\implies \dfrac{x}{-17 -93}  = \dfrac{y}{-124 +102} = \dfrac 1{-18-4}\\\\\\\implies -\dfrac{x}{110} = -\dfrac{y}{22} = -\dfrac 1{22}\\\\ \implies \dfrac{x}{110} = \dfrac{y}{22} = \dfrac 1{22}\\\ \\\text{Hence,}\\\\\\x=\dfrac{110}{22}=5,~~~~ y= \dfrac{22}{22} =1

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