The answer & explanation for this question is given in the attachment below.
Answer:
See explaination for the code
Explanation:
def wordsOfFrequency(words, freq):
d = {}
res = []
for i in range(len(words)):
if(words[i].lower() in d):
d[words[i].lower()] = d[words[i].lower()] + 1
else:
d[words[i].lower()] = 1
for word in words:
if d[word.lower()]==freq:
res.append(word)
return res
Note:
First a dictionary is created to keep the count of the lowercase form of each word.
Then, using another for loop, each word count is matched with the freq, if it matches, the word is appended to the result list res.
Finally the res list is appended.
Answer:
a load tester.
Explanation:
Based on the information provided within the question it can be said that in this situation the tool that you should use is known as a load tester. This tool allows you to test your servers in order to see how it behaves under both normal conditions as well as the anticipated peak load conditions that it may be encountering in the near future. Which is exactly what you need for your website.
The organization provides a free, online html5 validator application to ensure that a webpage's html tags follow the rules for html5 is the W3C.
<h3>What does the W3C do?</h3>
The W3C's is known to help to create protocols and rules that makes sure that long-term development of the Web.
Therefore, we can say that The organization provides a free, online html5 validator application to ensure that a webpage's html tags follow the rules for html5 is the W3C.
Learn more about The W3C from
brainly.com/question/11179793
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