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4 years ago

How can you solve real world mathematical problems using two linear equations in two variables

Computers and Technology

1 answer:

ipn [44]4 years ago

3 0

Answer:

import numpy as np

a = int(input ("Enter a"))

b = int(input ("Enter b"))

c = int(input ("Enter c"))

d = int(input ("Enter d"))

c1 = int(input ("Enter c1"))

c2 = int(input ("Enter c2"))

array1 =[[a, b],[c, d]]

A = np.array (array1)

B = np.array ([c1, c2])

X = np.linalg.inv (A).dot (B)

print (X)

Explanation:

let ax + by =c1

cx + dy =c2

We have used the above NumPy library that has the methods for matrix calculation, and here we have used matrix multiplication, and the inverse of a matrix to find the value of x and y.

We know AX=B

X = inv A. B

And this we have used above. We can calculate inv A and do matrix multiplication using NumPy. And thus we get the above solution.

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3 years ago

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Alina [70]

Answer:

In Java:

public static int[] inputArray(){

Scanner input = new Scanner(System.in);

int[] alpha = new int[20];

for(int i = 0;i<20;i++){

alpha[i] = input.nextInt();

}

return alpha;}

public static int[] doubleArray(int [] alpha){

int[] beta = new int[20];

for(int i = 0;i<20;i++){

beta[i] = 2 * alpha[i];

}

return beta;

}

public static int[] copyAlphaBeta(int [] alpha, int [] beta){

int [] AlphaBeta = new int[10];

for(int i = 0;i<5;i++){

AlphaBeta[i] = alpha[i];

}

int count = 5;

for(int i = 15;i<20;i++){

AlphaBeta[count] = beta[i];

count++;

}

return AlphaBeta;

}

public static void printArray(int [] alpha){

for(int i = 0;i<20;i++){

System.out.print(alpha[i]+" ");

if((i+1)%15 == 0){

System.out.println(" ");

}

Explanation:

The inputArray is defined here

public static int[] inputArray(){

Scanner input = new Scanner(System.in);

This declares alpha array of 20 elements

int[] alpha = new int[20];

The following iteration gets input from the user into the array

for(int i = 0;i<20;i++){

alpha[i] = input.nextInt();

}

This returns the alpha array

return alpha;}

The doubleArray is defined here. It takes the alpha array as its input parameter

public static int[] doubleArray(int [] alpha){

This declares beta of 20 integers

int[] beta = new int[20];

This populates beta by 2 * alpha[i]

for(int i = 0;i<20;i++){

beta[i] = 2 * alpha[i];

}

This returns the alpha array

return beta;}

The copyAlphaBeta array is defines here

public static int[] copyAlphaBeta(int [] alpha, int [] beta){

This declares AlphaBeta as 10 elements

int [] AlphaBeta = new int[10];

This populates the first 5 elements of AlphaBeta with the first 5 of alpha

for(int i = 0;i<5;i++){

AlphaBeta[i] = alpha[i];

}

int count = 5;

This populates the last 5 elements of AlphaBeta with the last 5 of beta

for(int i = 15;i<20;i++){

AlphaBeta[count] = beta[i];

count++;

}

This returns the AlphaBeta array

return AlphaBeta;

}

The printArray is defined here. It takes the alpha array as its input parameter

public static void printArray(int [] alpha){

This iterates through alpha array

for(int i = 0;i<20;i++){

This prints each element of the array

System.out.print(alpha[i]+" ");

A new line is started after the 15th element

if((i+1)%15 == 0){

System.out.println(" ");

}

}

See attachment for complete program which includes the main

Download txt

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3 years ago

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Answer:

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* It allows designer to express logic in plain natural language.

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* Unlike algorithms, pseudocodes are concise so pseudocodes are more readable and easier to modify.

Explanation:

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3 years ago

How can you solve real world mathematical problems using two linear equations in two variables​

How can you solve real world mathematical problems using two linear equations in two variables