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Margaret [11]
3 years ago
5

When computer network are joined together they form a bigger network called the​

Computers and Technology
1 answer:
Airida [17]3 years ago
8 0

Answer:

A WAN can be one large network or can consist of two or more lans connected together. The Internet is the world's largest wan.

Explanation:

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Advertising is organized around four distinct groups. The _____ group includes the photographers, the illustrators, video produc
borishaifa [10]

Answer:

Suppliers

Explanation:

There are <em>FOUR </em>distinct groups of Advertising namely:

  • The Advertisers
  • The Advertising Agencies
  • The Suppliers
  • Media

1.The Advertisers : clients

2.The Advertising Agencies: The companies that prepare promotional

   materials.

3.The Suppliers: Includes photographers, graphic designers, video recording

   specialists.

4.Media: launches the promotional/advertising campaigns in pursuit to reach

   the target audience.

4 0
3 years ago
A(n ____ is a named group of formatting characteristics.
Vsevolod [243]
I think the answer is style
7 0
3 years ago
Most keyboards today are in a
BlackZzzverrR [31]
Qwerty format I think.
6 0
3 years ago
X = 1 if (A = 1 OR B = 1) OR (A = 0 AND B = 1
Gnoma [55]

Answer:

For question a, it simplifies.  If you re-express it in boolean algebra, you get:

(a + b) + (!a + b)

= a + !a + b

= b

So you can simplify that circuit to just:

x = 1 if b = 1

(edit: or rather, x = b)

For question b, let's try it:

(!a!b)(!b + c)

= !a!b + !a!bc

= !a!b(1 + c)

= !a!b

So that one can be simplified to

a = 0 and b = 0

I have no good means of drawing them here, but hopefully the simplification helped!

4 0
3 years ago
Suppose that you are asked to modify the Stack class to add a new operation max() that returns the current maximum of the stack
Advocard [28]

Answer:

Following are the code to the given points:

Explanation:

For point 8.1:

public String max()//defining a method max

{

   String maxVal=null;//defining a string variable that holds a value

   for(int x=0;x<n;x++)

   {

       if(maxVal==null || a[i].compareTo(maxVal)>0)//defining if blok to comare the value

       {

           maxVal=a[i];//holding value in maxVal variable

       }

   }

   return maxVal;//return maxVal variable value

}

For point 8.2:

public void push(String item)//defining a method push that accepts item value in a parameter

{

       a[n]=item;//defining an array to hold item value

       if(n==0 || item.compareTo(maxVals[n-1])>0)//use if to comare item value

       {

               maxVals[n]=item;//holding item value in maxVals variable

       }

       else

       {

               maxVals[n]=maxVals[n-1];//decreasing the maxVals value

       }

       n++;//incrementing n value

}

public String pop()//defining a method pop

{

       return a[--n];//use return value

}

public String max()//defining a method max

{

       return maxVals[n-1];//return max value

}

  • In the first point, the max method is declared that compares the string and returns its max value.
  • In the second point, the push, pop, and max method are declared that works with their respective names like insert, remove and find max and after that, they return its value.
7 0
3 years ago
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